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What is the value of this expression when [tex]$x=-6$[/tex] and [tex]$y=-\frac{1}{2}$[/tex]?

[tex]4\left(x^2 + 3\right) - 2y[/tex]

A. -131
B. -35
C. [tex][tex]$57 \frac{1}{2}$[/tex][/tex]
D. 157


Sagot :

Certainly! Let's solve the problem step-by-step.

We are given the expression:
[tex]\[ 4(x^2 + 3) - 2y \][/tex]

We need to evaluate this expression for [tex]\( x = -6 \)[/tex] and [tex]\( y = -\frac{1}{2} \)[/tex].

### Step 1: Substitute [tex]\( x = -6 \)[/tex] and [tex]\( y = -\frac{1}{2} \)[/tex] into the expression

First, we substitute [tex]\( x = -6 \)[/tex]:
[tex]\[ x^2 = (-6)^2 = 36 \][/tex]

Now substitute this back into the expression:
[tex]\[ 4(x^2 + 3) - 2y = 4(36 + 3) - 2(-\frac{1}{2}) \][/tex]

### Step 2: Simplify inside the parentheses

Calculate inside the parentheses:
[tex]\[ 36 + 3 = 39 \][/tex]

So, the expression now reads:
[tex]\[ 4 \cdot 39 - 2(-\frac{1}{2}) \][/tex]

### Step 3: Multiply and simplify

Next, we perform the multiplication:
[tex]\[ 4 \cdot 39 = 156 \][/tex]

And simplify the -2 times [tex]\(-\frac{1}{2}\)[/tex]:
[tex]\[ -2 \times -\frac{1}{2} = 1 \][/tex]

So the expression now reads:
[tex]\[ 156 + 1 = 157 \][/tex]

Therefore, the value of the expression is:
[tex]\[ \boxed{157} \][/tex]

So, the correct answer is:
D. 157