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Solve [tex]$-6x + 3 \geq 21$[/tex]

A. [tex]$x \leq -3$[/tex]
B. [tex][tex]$x \geq -3$[/tex][/tex]
C. [tex]$x \leq 3$[/tex]
D. [tex]$x \geq 3$[/tex]


Sagot :

To solve the inequality [tex]\(-6x + 3 \geq 21\)[/tex], follow these steps:

1. Subtract 3 from both sides of the inequality:

[tex]\[ -6x + 3 - 3 \geq 21 - 3 \][/tex]

Simplifying this, we get:

[tex]\[ -6x \geq 18 \][/tex]

2. Divide both sides of the inequality by [tex]\(-6\)[/tex]:

When dividing both sides of an inequality by a negative number, the direction of the inequality sign must be flipped.

[tex]\[ x \leq \frac{18}{-6} \][/tex]

Simplifying the right-hand side, we have:

[tex]\[ x \leq -3 \][/tex]

The correct solution to the inequality is [tex]\(x \leq -3\)[/tex], which corresponds to option A.