From simple queries to complex problems, IDNLearn.com provides reliable answers. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.
Sagot :
To solve the inequality
[tex]\[ 8\left(\frac{1}{2} x - \frac{1}{4}\right) > 12 - 2x \][/tex]
we will proceed step-by-step:
1. Distribute the 8 inside the parentheses:
[tex]\[ 8 \left(\frac{1}{2} x - \frac{1}{4}\right) = 8 \cdot \frac{1}{2} x - 8 \cdot \frac{1}{4} \][/tex]
[tex]\[ = 4x - 2 \][/tex]
2. Rewrite the inequality:
[tex]\[ 4x - 2 > 12 - 2x \][/tex]
3. Add [tex]\(2x\)[/tex] to both sides to get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 4x - 2 + 2x > 12 - 2x + 2x \][/tex]
[tex]\[ 6x - 2 > 12 \][/tex]
4. Add 2 to both sides to isolate the term with [tex]\(x\)[/tex]:
[tex]\[ 6x - 2 + 2 > 12 + 2 \][/tex]
[tex]\[ 6x > 14 \][/tex]
5. Divide both sides by 6 to solve for [tex]\(x\)[/tex]:
[tex]\[ x > \frac{14}{6} \][/tex]
6. Simplify the fraction:
[tex]\[ x > \frac{14}{6} = \frac{7}{3} \][/tex]
The solution to the inequality is:
[tex]\[ x > \frac{7}{3} \][/tex]
Hence, the correct answer is:
A. [tex]\(x > \frac{7}{3}\)[/tex]
[tex]\[ 8\left(\frac{1}{2} x - \frac{1}{4}\right) > 12 - 2x \][/tex]
we will proceed step-by-step:
1. Distribute the 8 inside the parentheses:
[tex]\[ 8 \left(\frac{1}{2} x - \frac{1}{4}\right) = 8 \cdot \frac{1}{2} x - 8 \cdot \frac{1}{4} \][/tex]
[tex]\[ = 4x - 2 \][/tex]
2. Rewrite the inequality:
[tex]\[ 4x - 2 > 12 - 2x \][/tex]
3. Add [tex]\(2x\)[/tex] to both sides to get all [tex]\(x\)[/tex]-terms on one side:
[tex]\[ 4x - 2 + 2x > 12 - 2x + 2x \][/tex]
[tex]\[ 6x - 2 > 12 \][/tex]
4. Add 2 to both sides to isolate the term with [tex]\(x\)[/tex]:
[tex]\[ 6x - 2 + 2 > 12 + 2 \][/tex]
[tex]\[ 6x > 14 \][/tex]
5. Divide both sides by 6 to solve for [tex]\(x\)[/tex]:
[tex]\[ x > \frac{14}{6} \][/tex]
6. Simplify the fraction:
[tex]\[ x > \frac{14}{6} = \frac{7}{3} \][/tex]
The solution to the inequality is:
[tex]\[ x > \frac{7}{3} \][/tex]
Hence, the correct answer is:
A. [tex]\(x > \frac{7}{3}\)[/tex]
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.