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Find the slope, if it exists, of the line containing the pair of points.

[tex](8,9) \text{ and } (10,-7)[/tex]


Sagot :

To find the slope of the line containing the pair of points [tex]\((8, 9)\)[/tex] and [tex]\((10, -7)\)[/tex], follow these steps:

1. Identify the coordinates of the points:
- Point [tex]\((x_1, y_1)\)[/tex] is [tex]\((8, 9)\)[/tex]
- Point [tex]\((x_2, y_2)\)[/tex] is [tex]\((10, -7)\)[/tex]

2. Calculate the change in [tex]\(x\)[/tex] (denoted as [tex]\(\Delta x\)[/tex]):
[tex]\[ \Delta x = x_2 - x_1 \][/tex]
Substituting the given values:
[tex]\[ \Delta x = 10 - 8 = 2 \][/tex]

3. Calculate the change in [tex]\(y\)[/tex] (denoted as [tex]\(\Delta y\)[/tex]):
[tex]\[ \Delta y = y_2 - y_1 \][/tex]
Substituting the given values:
[tex]\[ \Delta y = -7 - 9 = -16 \][/tex]

4. Calculate the slope of the line:
The slope [tex]\(m\)[/tex] is given by the ratio of the change in [tex]\(y\)[/tex] to the change in [tex]\(x\)[/tex]:
[tex]\[ m = \frac{\Delta y}{\Delta x} \][/tex]
Substituting the values we calculated:
[tex]\[ m = \frac{-16}{2} = -8.0 \][/tex]

In summary:
- The change in [tex]\(x\)[/tex] ([tex]\(\Delta x\)[/tex]) is [tex]\(2\)[/tex].
- The change in [tex]\(y\)[/tex] ([tex]\(\Delta y\)[/tex]) is [tex]\(-16\)[/tex].
- The slope of the line is [tex]\(-8.0\)[/tex].