IDNLearn.com: Your trusted source for finding accurate and reliable answers. Join our community to access reliable and comprehensive responses to your questions from experienced professionals.
Sagot :
Let's analyze each equation to see if it represents a linear relationship.
1. Equation: [tex]\( 5 + 2y = 13 \)[/tex]
To determine if this equation represents a linear relationship, we'll solve for [tex]\( y \)[/tex]:
[tex]\[ 5 + 2y = 13 \][/tex]
Subtract 5 from both sides:
[tex]\[ 2y = 8 \][/tex]
Divide by 2:
[tex]\[ y = 4 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 0 \)[/tex] and [tex]\( b = 4 \)[/tex]. Therefore, this is a linear equation.
2. Equation: [tex]\( y = \frac{1}{2} x^2 + 7 \)[/tex]
This equation explicitly includes an [tex]\( x^2 \)[/tex] term, which means it is a quadratic equation, not linear. Linear equations can only have variables to the first power. Therefore, this is not a linear equation.
3. Equation: [tex]\( y - 5 = 2(x - 1) \)[/tex]
To determine if this equation represents a linear relationship, we'll rearrange it into the form [tex]\( y = mx + b \)[/tex]:
[tex]\[ y - 5 = 2(x - 1) \][/tex]
Distribute the 2 on the right side:
[tex]\[ y - 5 = 2x - 2 \][/tex]
Add 5 to both sides:
[tex]\[ y = 2x + 3 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 2 \)[/tex] and [tex]\( b = 3 \)[/tex]. Therefore, this is a linear equation.
4. Equation: [tex]\( \frac{y}{2} = x + 7 \)[/tex]
To determine if this equation represents a linear relationship, we'll solve for [tex]\( y \)[/tex]:
[tex]\[ \frac{y}{2} = x + 7 \][/tex]
Multiply both sides by 2:
[tex]\[ y = 2x + 14 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 2 \)[/tex] and [tex]\( b = 14 \)[/tex]. Therefore, this is a linear equation.
5. Equation: [tex]\( x = -4 \)[/tex]
This equation represents a vertical line on the coordinate plane, which means that [tex]\( x \)[/tex] remains constant and there is no dependence on [tex]\( y \)[/tex]. Such an equation is still considered linear, though it doesn't fit the [tex]\( y = mx + b \)[/tex] format because it is essentially of the form [tex]\( x = c \)[/tex] where [tex]\( c \)[/tex] represents a constant. Therefore, this is a linear equation.
Based on our analysis:
- Equation [tex]\( 5 + 2y = 13 \)[/tex] is not linear.
- Equation [tex]\( y = \frac{1}{2} x^2 + 7 \)[/tex] is not linear.
- Equation [tex]\( y - 5 = 2(x - 1) \)[/tex] is linear.
- Equation [tex]\( \frac{ y }{2}=x+7 \)[/tex] is linear.
- Equation [tex]\( x = -4 \)[/tex] is linear.
Thus, the equations that represent linear relationships are:
[tex]\[ y - 5 = 2(x - 1) \][/tex]
[tex]\[ \frac{ y }{2}=x+7 \][/tex]
[tex]\[ x=-4 \][/tex]
1. Equation: [tex]\( 5 + 2y = 13 \)[/tex]
To determine if this equation represents a linear relationship, we'll solve for [tex]\( y \)[/tex]:
[tex]\[ 5 + 2y = 13 \][/tex]
Subtract 5 from both sides:
[tex]\[ 2y = 8 \][/tex]
Divide by 2:
[tex]\[ y = 4 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 0 \)[/tex] and [tex]\( b = 4 \)[/tex]. Therefore, this is a linear equation.
2. Equation: [tex]\( y = \frac{1}{2} x^2 + 7 \)[/tex]
This equation explicitly includes an [tex]\( x^2 \)[/tex] term, which means it is a quadratic equation, not linear. Linear equations can only have variables to the first power. Therefore, this is not a linear equation.
3. Equation: [tex]\( y - 5 = 2(x - 1) \)[/tex]
To determine if this equation represents a linear relationship, we'll rearrange it into the form [tex]\( y = mx + b \)[/tex]:
[tex]\[ y - 5 = 2(x - 1) \][/tex]
Distribute the 2 on the right side:
[tex]\[ y - 5 = 2x - 2 \][/tex]
Add 5 to both sides:
[tex]\[ y = 2x + 3 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 2 \)[/tex] and [tex]\( b = 3 \)[/tex]. Therefore, this is a linear equation.
4. Equation: [tex]\( \frac{y}{2} = x + 7 \)[/tex]
To determine if this equation represents a linear relationship, we'll solve for [tex]\( y \)[/tex]:
[tex]\[ \frac{y}{2} = x + 7 \][/tex]
Multiply both sides by 2:
[tex]\[ y = 2x + 14 \][/tex]
This is a linear equation because it can be written in the form [tex]\( y = mx + b \)[/tex] where [tex]\( m = 2 \)[/tex] and [tex]\( b = 14 \)[/tex]. Therefore, this is a linear equation.
5. Equation: [tex]\( x = -4 \)[/tex]
This equation represents a vertical line on the coordinate plane, which means that [tex]\( x \)[/tex] remains constant and there is no dependence on [tex]\( y \)[/tex]. Such an equation is still considered linear, though it doesn't fit the [tex]\( y = mx + b \)[/tex] format because it is essentially of the form [tex]\( x = c \)[/tex] where [tex]\( c \)[/tex] represents a constant. Therefore, this is a linear equation.
Based on our analysis:
- Equation [tex]\( 5 + 2y = 13 \)[/tex] is not linear.
- Equation [tex]\( y = \frac{1}{2} x^2 + 7 \)[/tex] is not linear.
- Equation [tex]\( y - 5 = 2(x - 1) \)[/tex] is linear.
- Equation [tex]\( \frac{ y }{2}=x+7 \)[/tex] is linear.
- Equation [tex]\( x = -4 \)[/tex] is linear.
Thus, the equations that represent linear relationships are:
[tex]\[ y - 5 = 2(x - 1) \][/tex]
[tex]\[ \frac{ y }{2}=x+7 \][/tex]
[tex]\[ x=-4 \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.