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West Junior High needs to buy new fencing to go around its swimming pool. Determine the amount of fencing it will need by finding the perimeter of the pool.

Given:
[tex]\[ P = 2l + 2w \][/tex]
[tex]\[ l = 50 \text{ meters} \][/tex]
[tex]\[ w = 25 \text{ meters} \][/tex]

Evaluate the formula for the perimeter of a rectangle to solve the problem. Then check all that apply.

1. Write the formula for the perimeter of a rectangle:
[tex]\[ P = 2l + 2w \][/tex]

2. Use parentheses when you substitute 50 for [tex]\( l \)[/tex] and 25 for [tex]\( w \)[/tex]:
[tex]\[ P = 2(50) + 2(25) \][/tex]

3. After multiplying, add:
[tex]\[ P = 100 + 50 \][/tex]

4. The school needs 150 meters of fencing.

Check all that apply:
- The school needs 5,000 meters of fencing.
- The school needs 150 meters of fencing.


Sagot :

Certainly! Let's go through the problem step by step.

1. Write the formula for the perimeter of a rectangle:
The formula for the perimeter [tex]\( P \)[/tex] of a rectangle is:
[tex]\[ P = 2l + 2w \][/tex]
where [tex]\( l \)[/tex] is the length and [tex]\( w \)[/tex] is the width of the rectangle.

2. Substitute the given values for [tex]\( l \)[/tex] and [tex]\( w \)[/tex]:
We are given [tex]\( l = 50 \)[/tex] meters and [tex]\( w = 25 \)[/tex] meters. Substituting these values into the formula, we get:
[tex]\[ P = 2(50) + 2(25) \][/tex]

3. Perform the multiplication:
[tex]\[ 2 \times 50 = 100 \][/tex]
[tex]\[ 2 \times 25 = 50 \][/tex]

4. Add the results of the multiplication:
[tex]\[ P = 100 + 50 \][/tex]
[tex]\[ P = 150 \][/tex]

So, the school needs [tex]\( 150 \)[/tex] meters of fencing to go around the swimming pool.

Evaluation of the final statements:

- "The school needs 5,000 meters of fencing."
This is incorrect because, based on our calculations, the school needs 150 meters of fencing.

- "The school needs 150 meters of fencing."
This is correct because our calculated perimeter is precisely 150 meters.

Therefore, the correct amount of fencing needed is 150 meters.