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Gabe is the human resources manager for the Advanced Scientific Research Lab. He has to record the heights (in centimeters) and weights (in pounds) for each of the scientists in the lab.

\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|l|l|l|}
\hline
Height distribution (cm) & 178 & 163 & 174 & 186 & 154 & 167 & 167 & 181 & 159 & 165 & 177 & 191 & 158 \\
\hline
Weight distribution (lbs) & 157 & 163 & 190 & 187 & 183 & 173 & 184 & 189 & 193 & 192 & 177 & 173 & 168 \\
\hline
\end{tabular}

What are the medians for the height and weight distribution, respectively?

A. 170, 179
B. 183, 167
C. 167, 183
D. 179, 170
E. 165, 175


Sagot :

To determine the medians for the given height and weight distributions, we must follow these steps:

1. List the Heights and Weights:
The heights (in centimeters) are:
[tex]\[ 178, 163, 174, 186, 154, 167, 167, 181, 159, 165, 177, 191, 158 \][/tex]
The weights (in pounds) are:
[tex]\[ 157, 163, 190, 187, 183, 173, 184, 189, 193, 192, 177, 173, 168 \][/tex]

2. Sort the Height Values in Ascending Order:
Sorted heights:
[tex]\[ 154, 158, 159, 163, 165, 167, 167, 174, 177, 178, 181, 186, 191 \][/tex]

3. Sort the Weight Values in Ascending Order:
Sorted weights:
[tex]\[ 157, 163, 168, 173, 173, 177, 183, 184, 187, 189, 190, 192, 193 \][/tex]

4. Find the Median of the Heights:
- Since the number of height entries is 13 (odd), the median is the middle number.
- The middle number is the 7th value in this case (since [tex]\((13+1)/2 = 7\)[/tex]).

Hence, the height median is:
[tex]\[ 167 \][/tex]

5. Find the Median of the Weights:
- Similarly, the number of weight entries is 13 (odd), so the median is the middle number.
- The middle number is the 7th value in this case (since [tex]\((13+1)/2 = 7\)[/tex]).

Hence, the weight median is:
[tex]\[ 183 \][/tex]

The medians for the height and weight distributions are 167 cm and 183 lbs, respectively.

Therefore, the correct answer is:
[tex]\[ \boxed{C \; 167, 183} \][/tex]