Connect with experts and get insightful answers on IDNLearn.com. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.
Sagot :
To determine the likelihood that a student with siblings also has a pet, we are essentially looking for the conditional probability [tex]\( P(\text{Pet} \mid \text{Siblings}) \)[/tex].
Given:
- [tex]\( P(\text{Siblings}) = 0.75 \)[/tex] (The proportion of students with siblings)
- [tex]\( P(\text{Pet} \cap \text{Siblings}) = 0.30 \)[/tex] (The proportion of students who have both siblings and pets)
The conditional probability [tex]\( P(\text{Pet} \mid \text{Siblings}) \)[/tex] is calculated as:
[tex]\[ P(\text{Pet} \mid \text{Siblings}) = \frac{P(\text{Pet} \cap \text{Siblings})}{P(\text{Siblings})} \][/tex]
Plugging in the given values:
[tex]\[ P(\text{Pet} \mid \text{Siblings}) = \frac{0.30}{0.75} \][/tex]
Now, performing the division:
[tex]\[ P(\text{Pet} \mid \text{Siblings}) = 0.4 \][/tex]
Thus, the likelihood that a student with siblings also has a pet is 40%, which corresponds to option B.
So, the correct answer is:
B. [tex]\( 40 \% \)[/tex]
Given:
- [tex]\( P(\text{Siblings}) = 0.75 \)[/tex] (The proportion of students with siblings)
- [tex]\( P(\text{Pet} \cap \text{Siblings}) = 0.30 \)[/tex] (The proportion of students who have both siblings and pets)
The conditional probability [tex]\( P(\text{Pet} \mid \text{Siblings}) \)[/tex] is calculated as:
[tex]\[ P(\text{Pet} \mid \text{Siblings}) = \frac{P(\text{Pet} \cap \text{Siblings})}{P(\text{Siblings})} \][/tex]
Plugging in the given values:
[tex]\[ P(\text{Pet} \mid \text{Siblings}) = \frac{0.30}{0.75} \][/tex]
Now, performing the division:
[tex]\[ P(\text{Pet} \mid \text{Siblings}) = 0.4 \][/tex]
Thus, the likelihood that a student with siblings also has a pet is 40%, which corresponds to option B.
So, the correct answer is:
B. [tex]\( 40 \% \)[/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.