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If [tex]n=6[/tex], then [tex]2 \frac{1}{2n} - 1 \frac{1}{n} = [/tex]

A. [tex]\frac{5}{6}[/tex]
B. [tex]\frac{11}{12}[/tex]
C. [tex]1 \frac{1}{6}[/tex]
D. [tex]1 \frac{1}{3}[/tex]


Sagot :

To solve the expression [tex]\(2 \left( \frac{1}{2n} \right) - 1 \left( \frac{1}{n} \right)\)[/tex] with [tex]\(n = 6\)[/tex], we will break it down into smaller steps and solve each part.

1. First, substitute [tex]\(n = 6\)[/tex] into the expression:
[tex]\[ 2 \left( \frac{1}{2 \cdot 6} \right) - 1 \left( \frac{1}{6} \right) \][/tex]

2. Calculate the first term:
[tex]\[ 2 \left( \frac{1}{12} \right) \][/tex]
Simplify it:
[tex]\[ 2 \cdot \frac{1}{12} = \frac{2}{12} = \frac{1}{6} \][/tex]

3. Calculate the second term:
[tex]\[ -1 \left( \frac{1}{6} \right) \][/tex]
Simplify it:
[tex]\[ -1 \cdot \frac{1}{6} = -\frac{1}{6} \][/tex]

4. Add the two terms together:
[tex]\[ \frac{1}{6} + \left( -\frac{1}{6} \right) \][/tex]
Simplify it:
[tex]\[ \frac{1}{6} - \frac{1}{6} = 0 \][/tex]

Thus, the solution to the expression [tex]\(2 \left( \frac{1}{2n} \right) - 1 \left( \frac{1}{n} \right)\)[/tex] with [tex]\(n = 6\)[/tex] is [tex]\(0\)[/tex].

Therefore, none of the provided options [tex]\(\frac{5}{6}\)[/tex], [tex]\(\frac{11}{12}\)[/tex], [tex]\(1 \frac{1}{6}\)[/tex], [tex]\(1 \frac{1}{3}\)[/tex] are correct. The correct answer should be [tex]\(0\)[/tex], which is not listed among the given choices.
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