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Did Cherise use algebra tiles to correctly represent the product of [tex]$(x-2)(x-3)$[/tex]?

A. No, she did not multiply the [tex]x[/tex]-tiles by the negative integer tiles correctly.
B. No, she did not multiply the negative integer tiles by the other negative integer tiles correctly.
C. No, she did not add the terms together correctly.
D. Yes, the product is [tex]$x^2 - 5x - 6$[/tex].


Sagot :

To determine if Cherise used algebra tiles to correctly represent the product of [tex]\((x-2)(x-3)\)[/tex], let's go through the steps of expanding and simplifying this expression manually.

### Step-by-Step Expansion

1. Write the expression:
[tex]\[ (x-2)(x-3) \][/tex]

2. Apply the distributive property (also known as the FOIL method for binomials):
- First: [tex]\( x \cdot x \)[/tex]
- Outer: [tex]\( x \cdot (-3) \)[/tex]
- Inner: [tex]\((-2) \cdot x \)[/tex]
- Last: [tex]\((-2) \cdot (-3) \)[/tex]

3. Perform each multiplication:
- [tex]\( x \cdot x = x^2 \)[/tex]
- [tex]\( x \cdot (-3) = -3x \)[/tex]
- [tex]\((-2) \cdot x = -2x \)[/tex]
- [tex]\((-2) \cdot (-3) = 6 \)[/tex]

4. Combine all resulting terms:
[tex]\[ x^2 - 3x - 2x + 6 \][/tex]

5. Combine the like terms:
- Combine the [tex]\( x \)[/tex] terms: [tex]\(-3x\)[/tex] and [tex]\(-2x\)[/tex]:
[tex]\[ -3x - 2x = -5x \][/tex]

### Final Simplified Expression
By combining all the terms together, the final expression is:
[tex]\[ x^2 - 5x + 6 \][/tex]

### Evaluating Cherise's Representation
Cherise's goal is to represent the product as [tex]\(x^2 - 5x + 6\)[/tex]. According to the correct expansion:

1. Quadratic Term: [tex]\( x^2 \)[/tex] is correct.
2. Linear Term: [tex]\(-5x\)[/tex] is correct.
3. Constant Term: [tex]\( 6 \)[/tex] is correct.

Therefore, the final expression Cherise should have reached matches the result we calculated. Cherise correctly represented the product of [tex]\((x-2)(x-3)\)[/tex] as:

[tex]\[ x^2 - 5x + 6 \][/tex]

### Conclusion
Yes, the product is correctly represented by [tex]\( x^2 - 5x + 6 \)[/tex]. Thus, Cherise's representation is accurate.