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Find the common difference of the arithmetic sequence [tex]-4, -12, -20, \ldots[/tex]

[tex]\square[/tex]


Sagot :

Sure! Let's find the common difference of the arithmetic sequence [tex]\(-4, -12, -20, \ldots\)[/tex].

An arithmetic sequence is a sequence of numbers in which the difference of any two successive members is a constant, called the common difference.

Here's the step-by-step process:

1. Identify the first term of the sequence.
- The first term, [tex]\(a_1\)[/tex], is [tex]\(-4\)[/tex].

2. Identify the second term of the sequence.
- The second term, [tex]\(a_2\)[/tex], is [tex]\(-12\)[/tex].

3. To find the common difference ([tex]\(d\)[/tex]), subtract the first term from the second term.
[tex]\[ d = a_2 - a_1 \][/tex]

4. Substitute the values of [tex]\(a_2\)[/tex] and [tex]\(a_1\)[/tex]:
[tex]\[ d = -12 - (-4) \][/tex]

5. Simplify the expression:
[tex]\[ d = -12 + 4 \][/tex]

6. Complete the calculation:
[tex]\[ d = -8 \][/tex]

So, the common difference of the given arithmetic sequence [tex]\(-4, -12, -20, \ldots\)[/tex] is [tex]\(-8\)[/tex].

[tex]\[ \boxed{-8} \][/tex]