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The form of your answer should either be [tex]$p(x)$[/tex] or [tex]$p(x)+\frac{k}{x+1}$[/tex] where [tex][tex]$p(x)$[/tex][/tex] is a polynomial and [tex]$k$[/tex] is an integer.

[tex]\[ \frac{3x^3 + 10x^2 + 7x}{x+1} = \][/tex]
[tex]\[ \square \][/tex]


Sagot :

To solve the division of the polynomial expression [tex]\(\frac{3x^3 + 10x^2 + 7x}{x + 1}\)[/tex], we need to perform polynomial division. Let's go through the steps in detail:

1. Set up the division: We are dividing [tex]\(3x^3 + 10x^2 + 7x\)[/tex] by [tex]\(x + 1\)[/tex].

2. Divide the leading terms: The leading term of the numerator is [tex]\(3x^3\)[/tex], and the leading term of the denominator is [tex]\(x\)[/tex]. Dividing these gives:
[tex]\[ \frac{3x^3}{x} = 3x^2 \][/tex]
This is the first term of our quotient.

3. Multiply and subtract: Multiply the entire denominator [tex]\(x + 1\)[/tex] by the term [tex]\(3x^2\)[/tex] and subtract this product from the original polynomial:
[tex]\[ (3x^3 + 10x^2 + 7x) - (3x^2 \cdot (x + 1)) = 3x^3 + 10x^2 + 7x - (3x^3 + 3x^2) = (10x^2 - 3x^2) + 7x = 7x^2 + 7x \][/tex]

4. Repeat the process: Now we work with the new polynomial [tex]\(7x^2 + 7x\)[/tex]. Divide the leading term [tex]\(7x^2\)[/tex] by the leading term of the divisor [tex]\(x\)[/tex]:
[tex]\[ \frac{7x^2}{x} = 7x \][/tex]
This is the next term of our quotient.

5. Multiply and subtract again: Multiply the entire denominator [tex]\(x + 1\)[/tex] by [tex]\(7x\)[/tex] and subtract again:
[tex]\[ (7x^2 + 7x) - (7x \cdot (x + 1)) = 7x^2 + 7x - (7x^2 + 7x) = 0 \][/tex]
Since we are left with 0, there are no more terms to bring down, and the process stops here.

6. Quotient and remainder:
The quotient is [tex]\(3x^2 + 7x\)[/tex].
The remainder is [tex]\(0\)[/tex].

Thus, the final result of the division is given by the polynomial quotient [tex]\(3x^2 + 7x\)[/tex] with no remainder. Therefore, the expression simplifies to:

[tex]\[ \frac{3x^3 + 10x^2 + 7x}{x + 1} = 3x^2 + 7x \][/tex]

So the final answer is:
[tex]\[ 3x^2 + 7x \][/tex]
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