Experience the convenience of getting your questions answered at IDNLearn.com. Our platform offers detailed and accurate responses from experts, helping you navigate any topic with confidence.

Hl gas is added to the system at equilibrium below. How does the system adjust to reestablish equilibrium?

[tex]\[51.8 \text{ kJ} + H_2(g) + I_2(g) \rightleftharpoons 2 HI(g)\][/tex]

A. The reaction shifts to the left (reactants) and the concentrations of [tex]\(H_2\)[/tex] and [tex]\(I_2\)[/tex] decrease.

B. The reaction shifts to the right (products) and the concentrations of [tex]\(I_2\)[/tex] and [tex]\(H_2\)[/tex] increase.

C. The reaction shifts to the left (reactants) and the concentrations of [tex]\(H_2\)[/tex] and [tex]\(I_2\)[/tex] increase.

D. The reaction shifts to the right (products) and the concentrations of [tex]\(H_2\)[/tex] and [tex]\(I_2\)[/tex] decrease.


Sagot :

To determine how the system adjusts to re-establish equilibrium when [tex]\( HI \)[/tex] gas is added, we must consider Le Chatelier's Principle. Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change.

The given reaction is:

[tex]\[ 51.8 \, \text{kJ} + H_2(g) + I_2(g) \rightleftharpoons 2 HI(g) \][/tex]

With the addition of [tex]\( HI \)[/tex] gas, we are increasing the concentration of one of the products in the equilibrium system. According to Le Chatelier's Principle, the system will adjust to reduce the increased concentration of [tex]\( HI \)[/tex].

1. To reduce the concentration of [tex]\( HI \)[/tex], the system will shift the equilibrium position to the left, towards the reactants.
2. As the equilibrium shifts to the left, the quantities of [tex]\( H_2 \)[/tex] and [tex]\( I_2 \)[/tex] will increase to form more [tex]\( H_2 \)[/tex] and [tex]\( I_2 \)[/tex] while the amount of [tex]\( HI \)[/tex] will decrease.

Therefore, the correct adjustment:

- The reaction shifts to the left (towards the reactants).
- The concentrations of [tex]\( H_2 \)[/tex] and [tex]\( I_2 \)[/tex] will increase.

So, the correct answer is:

"The reaction shifts to the left (reactants) and the concentrations of [tex]\( H_2 \)[/tex] and [tex]\( I_2 \)[/tex] increase."