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Solve the equation [tex]$2x + 3y = 5$[/tex] for [tex]$x$[/tex].

A. [tex]$x = -3y + \frac{5}{2}$[/tex]
B. [tex][tex]$x = \frac{-3}{2}y + 5$[/tex][/tex]
C. [tex]$x = \frac{-3y + 5}{2}$[/tex]
D. [tex]$x = \frac{3y + 5}{2}$[/tex]


Sagot :

To solve the equation [tex]\(2x + 3y = 5\)[/tex] for [tex]\(x\)[/tex], follow these steps:

1. Isolate the term involving [tex]\(x\)[/tex]:
Start with the given equation.
[tex]\[ 2x + 3y = 5 \][/tex]
Subtract [tex]\(3y\)[/tex] from both sides to isolate the [tex]\(2x\)[/tex] term.
[tex]\[ 2x = 5 - 3y \][/tex]

2. Solve for [tex]\(x\)[/tex]:
Divide both sides of the equation by 2 to solve for [tex]\(x\)[/tex].
[tex]\[ x = \frac{5 - 3y}{2} \][/tex]

3. Simplify the expression:
The expression [tex]\(\frac{5 - 3y}{2}\)[/tex] cannot be simplified further in a way that results in a simpler or more conventional form.

So, the correct form of [tex]\(x\)[/tex] when isolating it in the equation [tex]\(2x + 3y = 5\)[/tex] is:
[tex]\[ x = \frac{5 - 3y}{2} \][/tex]

Now, comparing this with the provided choices:

1. [tex]\(x = -3y + \frac{5}{2}\)[/tex]
2. [tex]\(x = \frac{-3}{2} y + 5\)[/tex]
3. [tex]\(x = \frac{-3y + 5}{2}\)[/tex]
4. [tex]\(x = \frac{3y + 5}{2}\)[/tex]

The expression we derived, [tex]\(x = \frac{5 - 3y}{2}\)[/tex], matches the third option if you rearrange the numerator.

Therefore, the correct choice is:
[tex]\[ \boxed{\frac{-3y + 5}{2}} \][/tex]

This corresponds to the third option:
[tex]\[ x = \frac{-3y + 5}{2} \][/tex]
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