IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
To determine the equation of the linear function that best fits the given data points [tex]\((x, y)\)[/tex], we can follow these steps:
1. Collect the Given Data Points:
From the table, we have the following pairs of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] values:
[tex]\[ \begin{array}{cccc} (1, -6) & (3, 6) & (5, 18) & (7, 30) \\ \end{array} \][/tex]
2. Calculate the Slope and Intercept:
A linear function is of the form [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] is the slope and [tex]\(b\)[/tex] is the intercept.
Using linear regression techniques:
[tex]\[ m = \frac{(n \sum xy - \sum x \sum y)}{(n \sum x^2 - (\sum x)^2)} \\ b = \frac{(\sum y \sum x^2 - \sum x \sum xy)}{(n \sum x^2 - (\sum x)^2)} \][/tex]
where [tex]\(n\)[/tex] is the number of data points.
Given:
[tex]\[ \begin{align*} \sum x &= 1 + 3 + 5 + 7 = 16, \\ \sum y &= -6 + 6 + 18 + 30 = 48, \\ \sum xy &= 1(-6) + 3(6) + 5(18) + 7(30) = -6 + 18 + 90 + 210 = 312, \\ \sum x^2 &= 1^2 + 3^2 + 5^2 + 7^2 = 1 + 9 + 25 + 49 = 84. \end{align*} \][/tex]
Plugging these into the formulas:
[tex]\[ \begin{align*} m &= \frac{4 \cdot 312 - 16 \cdot 48}{4 \cdot 84 - 16^2} \\ &= \frac{1248 - 768}{336 - 256} \\ &= \frac{480}{80} \\ &= 6, \\ b &= \frac{48 \cdot 84 - 16 \cdot 312}{4 \cdot 84 - 16^2} \\ &= \frac{4032 - 4992}{336 - 256} \\ &= \frac{-960}{80} \\ &= -12. \end{align*} \][/tex]
3. Form the Linear Equation:
With the calculated slope [tex]\(m = 6\)[/tex] and intercept [tex]\(b = -12\)[/tex], the equation of the linear function is:
[tex]\[ y = 6x - 12. \][/tex]
Therefore, the correct equation that models the relationship between [tex]\(x\)[/tex] and [tex]\(y\)[/tex] as given in the table is:
[tex]\[ \boxed{y = 6x - 12} \][/tex]
1. Collect the Given Data Points:
From the table, we have the following pairs of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] values:
[tex]\[ \begin{array}{cccc} (1, -6) & (3, 6) & (5, 18) & (7, 30) \\ \end{array} \][/tex]
2. Calculate the Slope and Intercept:
A linear function is of the form [tex]\(y = mx + b\)[/tex], where [tex]\(m\)[/tex] is the slope and [tex]\(b\)[/tex] is the intercept.
Using linear regression techniques:
[tex]\[ m = \frac{(n \sum xy - \sum x \sum y)}{(n \sum x^2 - (\sum x)^2)} \\ b = \frac{(\sum y \sum x^2 - \sum x \sum xy)}{(n \sum x^2 - (\sum x)^2)} \][/tex]
where [tex]\(n\)[/tex] is the number of data points.
Given:
[tex]\[ \begin{align*} \sum x &= 1 + 3 + 5 + 7 = 16, \\ \sum y &= -6 + 6 + 18 + 30 = 48, \\ \sum xy &= 1(-6) + 3(6) + 5(18) + 7(30) = -6 + 18 + 90 + 210 = 312, \\ \sum x^2 &= 1^2 + 3^2 + 5^2 + 7^2 = 1 + 9 + 25 + 49 = 84. \end{align*} \][/tex]
Plugging these into the formulas:
[tex]\[ \begin{align*} m &= \frac{4 \cdot 312 - 16 \cdot 48}{4 \cdot 84 - 16^2} \\ &= \frac{1248 - 768}{336 - 256} \\ &= \frac{480}{80} \\ &= 6, \\ b &= \frac{48 \cdot 84 - 16 \cdot 312}{4 \cdot 84 - 16^2} \\ &= \frac{4032 - 4992}{336 - 256} \\ &= \frac{-960}{80} \\ &= -12. \end{align*} \][/tex]
3. Form the Linear Equation:
With the calculated slope [tex]\(m = 6\)[/tex] and intercept [tex]\(b = -12\)[/tex], the equation of the linear function is:
[tex]\[ y = 6x - 12. \][/tex]
Therefore, the correct equation that models the relationship between [tex]\(x\)[/tex] and [tex]\(y\)[/tex] as given in the table is:
[tex]\[ \boxed{y = 6x - 12} \][/tex]
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.