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Sagot :
Alright, let's solve this step by step.
1. Understanding the Problem: We have a cube numbered from 0 to 5. This means the cube has 6 faces, each with a unique number ranging from 0 to 5. We want to find out how many times the number 5 will turn up if we throw the cube 120 times.
2. Determine the Probability of Rolling a 5:
- Since each of the 6 faces has an equal chance of landing face up, the probability of any specific number, including 5, turning up on a single throw is [tex]\( \frac{1}{6} \)[/tex].
3. Calculate the Expected Number of Times 5 Appears in 120 Throws:
- The total number of throws is 120.
- Therefore, the expected number of times the number 5 turns up is calculated by multiplying the total number of throws by the probability of rolling a 5.
[tex]\[ \text{Expected count of 5s} = 120 \times \frac{1}{6} \][/tex]
4. Perform the Multiplication:
[tex]\[ 120 \times \frac{1}{6} = 20 \][/tex]
So, the number 5 is expected to turn up 20 times when the cube is thrown 120 times.
The correct answer is:
A 20
1. Understanding the Problem: We have a cube numbered from 0 to 5. This means the cube has 6 faces, each with a unique number ranging from 0 to 5. We want to find out how many times the number 5 will turn up if we throw the cube 120 times.
2. Determine the Probability of Rolling a 5:
- Since each of the 6 faces has an equal chance of landing face up, the probability of any specific number, including 5, turning up on a single throw is [tex]\( \frac{1}{6} \)[/tex].
3. Calculate the Expected Number of Times 5 Appears in 120 Throws:
- The total number of throws is 120.
- Therefore, the expected number of times the number 5 turns up is calculated by multiplying the total number of throws by the probability of rolling a 5.
[tex]\[ \text{Expected count of 5s} = 120 \times \frac{1}{6} \][/tex]
4. Perform the Multiplication:
[tex]\[ 120 \times \frac{1}{6} = 20 \][/tex]
So, the number 5 is expected to turn up 20 times when the cube is thrown 120 times.
The correct answer is:
A 20
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