From beginner to expert, IDNLearn.com has answers for everyone. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

Which is true about the completely simplified difference of the polynomials [tex]$a^3 b + 9 a^2 b^2 - 4 a b^5$[/tex] and [tex]$a^3 b - 3 a^2 b^2 + a b^5$[/tex]?

A. The difference is a binomial with a degree of 5.
B. The difference is a binomial with a degree of 6.
C. The difference is a trinomial with a degree of 5.
D. The difference is a trinomial with a degree of 6.


Sagot :

Let’s solve the problem step by step.

We have two polynomials:
[tex]\[ P_1(a, b) = a^3 b + 9 a^2 b^2 - 4 a b^5 \][/tex]
[tex]\[ P_2(a, b) = a^3 b - 3 a^2 b^2 + a b^5 \][/tex]

First, compute the difference between these two polynomials:
[tex]\[ P_1(a, b) - P_2(a, b) \][/tex]

Simplify the subtraction term by term:
1. For the term [tex]\(a^3 b\)[/tex]:
[tex]\[ a^3 b - a^3 b = 0 \][/tex]

2. For the term [tex]\(9 a^2 b^2\)[/tex]:
[tex]\[ 9 a^2 b^2 - (-3 a^2 b^2) = 9 a^2 b^2 + 3 a^2 b^2 = 12 a^2 b^2 \][/tex]

3. For the term [tex]\(-4 a b^5\)[/tex]:
[tex]\[ -4 a b^5 - a b^5 = -4 a b^5 - 1 a b^5 = -5 a b^5 \][/tex]

Thus, the simplified polynomial difference is:
[tex]\[ P_1(a, b) - P_2(a, b) = 0 + 12 a^2 b^2 - 5 a b^5 \][/tex]
[tex]\[ P_1(a, b) - P_2(a, b) = 12 a^2 b^2 - 5 a b^5 \][/tex]

Now, let’s analyze the resulting polynomial [tex]\(12 a^2 b^2 - 5 a b^5\)[/tex]:
- The polynomial has 2 terms.
- The degree of a term is the sum of the exponents of [tex]\(a\)[/tex] and [tex]\(b\)[/tex]. For [tex]\(12 a^2 b^2\)[/tex], the degree is [tex]\(2 + 2 = 4\)[/tex]. For [tex]\(-5 a b^5\)[/tex], the degree is [tex]\(1 + 5 = 6\)[/tex].

Since the term [tex]\(-5 a b^5\)[/tex] has the highest degree, the resulting polynomial has a degree of 6.

To summarize:
- The difference is a binomial (since it has 2 terms).
- The degree of the difference is 6.

Therefore, the correct and true statement is:
The difference is a binomial with a degree of 6.