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\begin{tabular}{|c|c|}
\hline
2 & 16 \\
\hline
3 & 14 \\
\hline
4 & 20 \\
\hline
5 & 12 \\
\hline
6 & 17 \\
\hline
\end{tabular}

Which statements below represent the situation? Select three options.

A. The relative frequency of rolling a 4 is [tex] \frac{2}{9} [/tex].

B. The experimental probability of rolling a 3 is greater than the theoretical probability of rolling a 3.

C. The experimental probability of rolling a 2 is greater than the theoretical probability of rolling a 2.

D. The relative frequency of rolling a 5 is [tex] \frac{2}{13} [/tex].

E. The experimental probability of rolling a 1 is less than the experimental probability of rolling a 6.


Sagot :

To solve this problem, let's go through each statement and determine if it accurately represents the situation based on the given data.

First, let's repeat the data provided in the table:
- 2 is rolled 16 times.
- 3 is rolled 14 times.
- 4 is rolled 20 times.
- 5 is rolled 12 times.
- 6 is rolled 17 times.

The total number of outcomes is:
[tex]\[ 16 + 14 + 20 + 12 + 17 = 79 \][/tex]

Next, let's evaluate each of the statements.

1. The relative frequency of rolling a 4 is [tex]\(\frac{2}{9}\)[/tex].
- The relative frequency of rolling a 4 is calculated as the number of times 4 is rolled divided by the total number of outcomes:
[tex]\[ \text{Relative frequency of 4} = \frac{20}{79} \][/tex]
- We need to check if [tex]\(\frac{20}{79}\)[/tex] is equal to [tex]\(\frac{2}{9}\)[/tex]. Since
[tex]\(\frac{20}{79}\)[/tex] is not equal to [tex]\(\frac{2}{9}\)[/tex], this statement is False.

2. The experimental probability of rolling a 3 is greater than the theoretical probability of rolling a 3.
- The experimental probability of rolling a 3 is:
[tex]\[ \text{Experimental probability of 3} = \frac{14}{79} \][/tex]
- The theoretical probability of rolling a 3 with a fair 6-sided die is:
[tex]\[ \text{Theoretical probability of 3} = \frac{1}{6} \][/tex]
- Comparing [tex]\(\frac{14}{79}\)[/tex] and [tex]\(\frac{1}{6}\)[/tex], we find that [tex]\(\frac{14}{79}\)[/tex] is indeed greater than [tex]\(\frac{1}{6}\)[/tex]. Therefore, this statement is True.

3. The experimental probability of rolling a 2 is greater than the theoretical probability of rolling a 2.
- The experimental probability of rolling a 2 is:
[tex]\[ \text{Experimental probability of 2} = \frac{16}{79} \][/tex]
- The theoretical probability of rolling a 2 is:
[tex]\[ \text{Theoretical probability of 2} = \frac{1}{6} \][/tex]
- Since [tex]\(\frac{16}{79}\)[/tex] is greater than [tex]\(\frac{1}{6}\)[/tex], this statement is True.

4. The relative frequency of rolling a 5 is [tex]\(\frac{2}{13}\)[/tex].
- The relative frequency of rolling a 5 is:
[tex]\[ \text{Relative frequency of 5} = \frac{12}{79} \][/tex]
- We need to check if [tex]\(\frac{12}{79}\)[/tex] is equal to [tex]\(\frac{2}{13}\)[/tex]. Since
[tex]\(\frac{12}{79}\)[/tex] is not equal to [tex]\(\frac{2}{13}\)[/tex], this statement is False.

5. The experimental probability of rolling a 1 is less than the experimental probability of rolling a 6.
- From the given data, a 1 is never rolled, so:
[tex]\[ \text{Experimental probability of 1} = 0 \][/tex]
- The experimental probability of rolling a 6 is:
[tex]\[ \text{Experimental probability of 6} = \frac{17}{79} \][/tex]
- Since [tex]\(0\)[/tex] is certainly less than [tex]\(\frac{17}{79}\)[/tex], this statement is True.

Given the evaluations, the three correct statements representing the situation are:

- The experimental probability of rolling a 3 is greater than the theoretical probability of rolling a 3. (True)
- The experimental probability of rolling a 2 is greater than the theoretical probability of rolling a 2. (True)
- The experimental probability of rolling a 1 is less than the experimental probability of rolling a 6. (True)