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On a number line, point D is at -6, and point E is at 8. Point F lies between points D and E. If [tex]$DF:FE$[/tex] is [tex]$3:1$[/tex], where does point F lie on the number line?

Point [tex][tex]$F$[/tex][/tex] is at [tex]\square[/tex] on the number line.


Sagot :

Let's solve the problem step-by-step.

1. Identify the positions of points D and E on the number line:
- Point D is at -6.
- Point E is at 8.

2. Understand the given ratio DF : FE which is 3 : 1:
This means that the total distance between D and E is divided into 3 parts for DF and 1 part for FE.

3. Calculate the total number of parts:
Since the ratio is 3 : 1, the total number of parts is [tex]\(3 + 1 = 4\)[/tex].

4. Determine the total distance between D (-6) and E (8):
To find this distance, subtract the position of D from the position of E:
[tex]\[ \text{Distance DE} = 8 - (-6) = 8 + 6 = 14 \][/tex]

5. Calculate the length of one part:
The total distance (14) divided by the total number of parts (4) gives the length of one part:
[tex]\[ \text{Length of one part} = \frac{14}{4} = 3.5 \][/tex]

6. Find the position of F:
Since DF consists of 3 parts and each part is 3.5 units long, the position of F is:
[tex]\[ \text{Position of F} = (-6) + 3 \times 3.5 \][/tex]
Calculate this step-by-step:
[tex]\[ 3 \times 3.5 = 10.5 \][/tex]
[tex]\[ (-6) + 10.5 = 4.5 \][/tex]

So, point F is at 4.5 on the number line.

Therefore, the correct answer from the drop-down menu is:

Point [tex]$F$[/tex] is at [tex]\(\boxed{4.5}\)[/tex] on the number line.