Get the most out of your questions with the extensive resources available on IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.
Sagot :
To divide the polynomial [tex]\( f(x) \)[/tex] by [tex]\( d(x) \)[/tex], we aim to express the division in the following format:
[tex]\[ \frac{f(x)}{d(x)}=Q(x)+\frac{R(x)}{d(x)} \][/tex]
where [tex]\( Q(x) \)[/tex] is the quotient and [tex]\( R(x) \)[/tex] is the remainder.
Given the polynomials:
[tex]\[ f(x) = x^4 - 35x^2 \][/tex]
[tex]\[ d(x) = x + 6 \][/tex]
When we perform the polynomial division of [tex]\( f(x) \)[/tex] by [tex]\( d(x) \)[/tex], we obtain:
[tex]\[ Q(x) = x^3 - 6x^2 + x - 6 \][/tex]
[tex]\[ R(x) = 36 \][/tex]
Thus, our division can be represented as:
[tex]\[ \frac{x^4 - 35x^2}{x + 6} = \left( x^3 - 6x^2 + x - 6 \right) + \frac{36}{x + 6} \][/tex]
So, our final answer in the specified format is:
[tex]\[ \begin{array}{c} \frac{f(x)}{d(x)}=Q(x)+\frac{R(x)}{d(x)} \\ \frac{f(x)}{d(x)}=\frac{x^4-35 x^2}{x+6} \\ R(x)=[36] \end{array} \][/tex]
[tex]\[ \frac{f(x)}{d(x)}=Q(x)+\frac{R(x)}{d(x)} \][/tex]
where [tex]\( Q(x) \)[/tex] is the quotient and [tex]\( R(x) \)[/tex] is the remainder.
Given the polynomials:
[tex]\[ f(x) = x^4 - 35x^2 \][/tex]
[tex]\[ d(x) = x + 6 \][/tex]
When we perform the polynomial division of [tex]\( f(x) \)[/tex] by [tex]\( d(x) \)[/tex], we obtain:
[tex]\[ Q(x) = x^3 - 6x^2 + x - 6 \][/tex]
[tex]\[ R(x) = 36 \][/tex]
Thus, our division can be represented as:
[tex]\[ \frac{x^4 - 35x^2}{x + 6} = \left( x^3 - 6x^2 + x - 6 \right) + \frac{36}{x + 6} \][/tex]
So, our final answer in the specified format is:
[tex]\[ \begin{array}{c} \frac{f(x)}{d(x)}=Q(x)+\frac{R(x)}{d(x)} \\ \frac{f(x)}{d(x)}=\frac{x^4-35 x^2}{x+6} \\ R(x)=[36] \end{array} \][/tex]
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.