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In the previous question, after Akbar and Birbal meet, they chat for half an hour and then leave for their respective homes. At what time will they reach home? [tex]1: 30 pm[/tex]

Daisy Duck and Donald Duck start moving towards each other from their homes, 24 km apart, at noon. Daisy walks at a constant speed of 5 km/h, while Donald walks at a constant speed of 7 km/h. How far away from each other will they be 10 minutes before they meet?


Sagot :

To solve this problem, we need to determine the distance between Daisy Duck and Donald Duck 10 minutes before they meet. Here are the steps to find the solution:

1. Calculate their combined speed:
Daisy's speed = 5 kmph,
Donald's speed = 7 kmph,
Combined speed (when moving towards each other) = 5 kmph + 7 kmph = 12 kmph.

2. Calculate the time it takes for them to meet:
Distance between them = 24 km,
Time to meet = Distance / Combined speed = 24 km / 12 kmph = 2 hours.

3. Convert 10 minutes to hours:
10 minutes = 10/60 hours = 1/6 hours ≈ 0.1667 hours.

4. Calculate the time they have traveled before the 10 minutes mark:
Time before they meet = Time to meet - 10 minutes in hours = 2 hours - 0.1667 hours ≈ 1.8333 hours.

5. Calculate the distance each has covered in that time:
- Daisy's distance = Daisy's speed Time before they meet = 5 kmph 1.8333 hours ≈ 9.1667 km.
- Donald's distance = Donald's speed Time before they meet = 7 kmph 1.8333 hours ≈ 12.8333 km.

6. Determine the remaining distance between them 10 minutes before they meet:
- Total distance initially = 24 km,
- Total distance covered by both before 10 minutes = Daisy's distance + Donald's distance = 9.1667 km + 12.8333 km ≈ 22 km,
- Remaining distance = Initial distance - Total distance covered = 24 km - 22 km = 2 km.

Therefore, Daisy Duck and Donald Duck will be 2 km away from each other 10 minutes before they meet.
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