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Question 5

Evaluate: [tex]\( g(n) = n^2 - 5n^2 ; n = -4n + 1 \)[/tex]

Answer format: (Example) [tex]\( 25n^{\wedge} 2 + 4 \)[/tex]

[tex]\(\square\)[/tex]

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Sagot :

To solve the given problem step-by-step, follow these procedures:

1. Given function:
[tex]\[ g(n) = n^2 - 5n^2 \][/tex]

2. Simplify the expression for [tex]\( g(n) \)[/tex]:
[tex]\[ g(n) = n^2 - 5n^2 = -4n^2 \][/tex]

3. Substitute [tex]\( n \)[/tex] with [tex]\((n' = -4n + 1)\)[/tex] in the simplified function [tex]\( g(n) = -4n^2 \)[/tex], meaning, we need to find [tex]\( g(-4n + 1) \)[/tex]:

Let's denote [tex]\( n' = -4n + 1 \)[/tex], and substitute [tex]\( n' \)[/tex] into the expression:
[tex]\[ g(n') = -4(n')^2 \][/tex]

4. Substitute the value of [tex]\( n' = -4n + 1 \)[/tex] into [tex]\( g(n') \)[/tex]:
[tex]\[ g(-4n + 1) = -4((-4n + 1))^2 \][/tex]

5. Simplify the expression:

Expanding the square:
[tex]\[ (-4n + 1)^2 = (1 - 4n)^2 = (1 - 4n)(1 - 4n) = 1 - 8n + 16n^2 \][/tex]

Substituting back into [tex]\( g(-4n + 1) \)[/tex]:
[tex]\[ g(-4n + 1) = -4(1 - 8n + 16n^2) = -4 + 32n - 64n^2 \][/tex]

Therefore, the simplified functions for [tex]\( g \)[/tex] and [tex]\( g \)[/tex] when substituting [tex]\( n \)[/tex] with [tex]\((-4n + 1)\)[/tex] are:
[tex]\[ g(n) = -4n^2 \][/tex]
and
[tex]\[ g(-4n + 1) = -4(1 - 4n)^2 \][/tex]

Expressing this result in the required format:
[tex]\[ g(n) = -4 n^{\wedge} 2 \][/tex]
and
[tex]\[ g(-4n + 1) = -4 (1 - 4 n)^{\wedge} 2 \][/tex]