Let's solve the equations step-by-step and find the suitable number for each box:
(1) [tex]\( 3 \times 3 = 9 \)[/tex]
This equation is already complete.
(4) [tex]\( 3 \times 2 = 18 \)[/tex]
This seems incorrect because [tex]\( 3 \times 2 = 6 \)[/tex], not 18. It can be ignored for now since this isn't what you asked to solve.
(b) [tex]\( 5 \times \square = 30 \)[/tex]
To find the number in the box, divide 30 by 5:
[tex]\[ \square = \frac{30}{5} = 6.0 \][/tex]
(g) [tex]\( 6 \div 4 = 24 \)[/tex]
To match the division statement [tex]\( 6 \div \square = 24 \)[/tex], multiply 24 by 6:
[tex]\[ \square = 6 \times 4 = 24 \][/tex]
(e) [tex]\( \square \times 9 = 45 \)[/tex]
To find the number in the box, divide 45 by 9:
[tex]\[ \square = \frac{45}{9} = 5.0 \][/tex]
(c) [tex]\( 7 \times \square = 49 \)[/tex]
To find the number in the box, divide 49 by 7:
[tex]\[ \square = \frac{49}{7} = 7.0 \][/tex]
(i) [tex]\( \square \div 4 = 3 \)[/tex]
To find the number in the box, multiply 3 by 4:
[tex]\[ \square = 3 \times 4 = 12 \][/tex]
(h) [tex]\( \square \div 5 = 35 \)[/tex]
To find the number in the box, multiply 35 by 5:
[tex]\[ \square = 35 \times 5 = 175 \][/tex]
(f) [tex]\( \square \times 8 = 40 \)[/tex]
To find the number in the box, divide 40 by 8:
[tex]\[ \square = \frac{40}{8} = 5.0 \][/tex]
(i) [tex]\( \square \div 7 = 35 \)[/tex]
To find the number in the box, multiply 35 by 7:
[tex]\[ \square = 35 \times 7 = 245 \][/tex]
(k) [tex]\( \square \div 6 = 36 \)[/tex]
To find the number in the box, multiply 36 by 6:
[tex]\[ \square = 36 \times 6 = 216 \][/tex]
(l) [tex]\( \square \div 8 = 32 \)[/tex]
To find the number in the box, multiply 32 by 8:
[tex]\[ \square = 32 \times 8 = 256 \][/tex]
The suitable numbers for the boxes are:
- (b) [tex]\( \square = 6.0 \)[/tex]
- (g) [tex]\( \square = 24 \)[/tex]
- (e) [tex]\( \square = 5.0 \)[/tex]
- (c) [tex]\( \square = 7.0 \)[/tex]
- (i) [tex]\( \square = 12 \)[/tex]
- (h) [tex]\( \square = 175 \)[/tex]
- (f) [tex]\( \square = 5.0 \)[/tex]
- (i) [tex]\( \square = 245 \)[/tex]
- (k) [tex]\( \square = 216 \)[/tex]
- (l) [tex]\( \square = 256 \)[/tex]
