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Sagot :
To solve the system of equations using the elimination method, we start by writing down the given equations:
[tex]\[ \frac{1}{x} + \frac{1}{y} = 5 \quad \text{(1)} \][/tex]
[tex]\[ \frac{1}{y} + \frac{1}{x} = 1 \quad \text{(2)} \][/tex]
We observe that equations (1) and (2) are identical. Thus, these equations are in essence saying the same thing and represent a single line in the xy-plane, not two distinct lines. Let us be clear that the system has no unique solution because the two equations are dependent and repeat the same relationship, i.e.,
[tex]\[ \frac{1}{x} + \frac{1}{y} = 5 \quad \text{and} \quad \frac{1}{x} + \frac{1}{y} = 1 \][/tex]
Since the equations effectively represent the same relationship, and since [tex]\(5 \neq 1\)[/tex], this system is contradictory and inconsistent. There are no values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that can satisfy both equations simultaneously. Therefore, the system has no solution.
[tex]\[ \frac{1}{x} + \frac{1}{y} = 5 \quad \text{(1)} \][/tex]
[tex]\[ \frac{1}{y} + \frac{1}{x} = 1 \quad \text{(2)} \][/tex]
We observe that equations (1) and (2) are identical. Thus, these equations are in essence saying the same thing and represent a single line in the xy-plane, not two distinct lines. Let us be clear that the system has no unique solution because the two equations are dependent and repeat the same relationship, i.e.,
[tex]\[ \frac{1}{x} + \frac{1}{y} = 5 \quad \text{and} \quad \frac{1}{x} + \frac{1}{y} = 1 \][/tex]
Since the equations effectively represent the same relationship, and since [tex]\(5 \neq 1\)[/tex], this system is contradictory and inconsistent. There are no values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex] that can satisfy both equations simultaneously. Therefore, the system has no solution.
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