Discover new information and insights with the help of IDNLearn.com. Get step-by-step guidance for all your technical questions from our dedicated community members.
Sagot :
To find the complement of set [tex]\( A \)[/tex], denoted [tex]\(\bar{A}\)[/tex], we need to determine which elements are in the universal set [tex]\( U \)[/tex] but not in set [tex]\( A \)[/tex].
Given:
- Universal set [tex]\( U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} \)[/tex]
- Set [tex]\( A = \{2, 4, 5\} \)[/tex]
The complement of [tex]\( A \)[/tex], [tex]\(\bar{A}\)[/tex], includes all the elements in [tex]\( U \)[/tex] that are not in [tex]\( A \)[/tex].
So, we remove the elements of [tex]\( A \)[/tex] from [tex]\( U \)[/tex]:
- Start with the universal set [tex]\( U \)[/tex]: \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}
- Remove 2 (in [tex]\( A \)[/tex]): \{1, 3, 4, 5, 6, 7, 8, 9, 10\}
- Remove 4 (in [tex]\( A \)[/tex]): \{1, 3, 5, 6, 7, 8, 9, 10\}
- Remove 5 (in [tex]\( A \)[/tex]): \{1, 3, 6, 7, 8, 9, 10\}
Thus, the elements that remain are \{1, 3, 6, 7, 8, 9, 10\}.
Therefore, the complement of [tex]\( A \)[/tex] is:
[tex]\[ \bar{A} = \{1, 3, 6, 7, 8, 9, 10\} \][/tex]
Therefore, the correct answer is:
A. [tex]\( \bar{A} = \{1, 3, 6, 7, 8, 9, 10\} \)[/tex]
Given:
- Universal set [tex]\( U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\} \)[/tex]
- Set [tex]\( A = \{2, 4, 5\} \)[/tex]
The complement of [tex]\( A \)[/tex], [tex]\(\bar{A}\)[/tex], includes all the elements in [tex]\( U \)[/tex] that are not in [tex]\( A \)[/tex].
So, we remove the elements of [tex]\( A \)[/tex] from [tex]\( U \)[/tex]:
- Start with the universal set [tex]\( U \)[/tex]: \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}
- Remove 2 (in [tex]\( A \)[/tex]): \{1, 3, 4, 5, 6, 7, 8, 9, 10\}
- Remove 4 (in [tex]\( A \)[/tex]): \{1, 3, 5, 6, 7, 8, 9, 10\}
- Remove 5 (in [tex]\( A \)[/tex]): \{1, 3, 6, 7, 8, 9, 10\}
Thus, the elements that remain are \{1, 3, 6, 7, 8, 9, 10\}.
Therefore, the complement of [tex]\( A \)[/tex] is:
[tex]\[ \bar{A} = \{1, 3, 6, 7, 8, 9, 10\} \][/tex]
Therefore, the correct answer is:
A. [tex]\( \bar{A} = \{1, 3, 6, 7, 8, 9, 10\} \)[/tex]
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.