Get comprehensive answers to your questions with the help of IDNLearn.com's community. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.
Sagot :
To determine the amount of force needed to push Jeff's race car, we will use the formula for force in physics:
[tex]\[ F = m \cdot a \][/tex]
where:
- [tex]\( F \)[/tex] represents the force in Newtons (N),
- [tex]\( m \)[/tex] is the mass of the object in kilograms (kg),
- [tex]\( a \)[/tex] is the acceleration in meters per second squared (m/s²).
We are given:
- [tex]\( m = 750 \, \text{kg} \)[/tex]
- [tex]\( a = 2.5 \, \text{m/s}^2 \)[/tex]
Substitute the given values into the formula:
[tex]\[ F = 750 \, \text{kg} \cdot 2.5 \, \text{m/s}^2 \][/tex]
Multiplying the values together:
[tex]\[ F = 1875 \, \text{N} \][/tex]
Thus, the amount of force needed to push Jeff's race car is [tex]\( 1875 \)[/tex] Newtons.
[tex]\[ F = m \cdot a \][/tex]
where:
- [tex]\( F \)[/tex] represents the force in Newtons (N),
- [tex]\( m \)[/tex] is the mass of the object in kilograms (kg),
- [tex]\( a \)[/tex] is the acceleration in meters per second squared (m/s²).
We are given:
- [tex]\( m = 750 \, \text{kg} \)[/tex]
- [tex]\( a = 2.5 \, \text{m/s}^2 \)[/tex]
Substitute the given values into the formula:
[tex]\[ F = 750 \, \text{kg} \cdot 2.5 \, \text{m/s}^2 \][/tex]
Multiplying the values together:
[tex]\[ F = 1875 \, \text{N} \][/tex]
Thus, the amount of force needed to push Jeff's race car is [tex]\( 1875 \)[/tex] Newtons.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.