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Find the solution to this system of equations.

[tex]\[
\begin{array}{l}
x - y + 2z = 0 \\
x - 2y + 3z = -1 \\
2x - 2y + z = 1 \\
x = \square \\
y = \square \\
z = \square
\end{array}
\][/tex]

Sagot :

GinnyAnsweridn
To find the solution to the system of equations given by:

[tex]\[ \begin{array}{l} x-y+2z=0 \\ x-2y+3z=-1 \\ 2x-2y+z=1 \\ \end{array} \][/tex]

we will employ the method of solving a system of linear equations. Upon solving, we find the following values for [tex]\( x \)[/tex], [tex]\( y \)[/tex], and [tex]\( z \)[/tex]:

[tex]\[ \begin{array}{l} x = \frac{4}{3} \\ y = \frac{2}{3} \\ z = -\frac{1}{3} \\ \end{array} \][/tex]

So the correct values for each variable are:

[tex]\[ x = 1.3333333333333335 \\ y = 0.6666666666666667 \\ z = -0.3333333333333333 \\ \][/tex]

Therefore,

[tex]\[ x = \box{1.3333333333333335} \\ y = \box{0.6666666666666667} \\ z = \box{-0.3333333333333333} \\ \][/tex]
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