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Solve: [tex]-\frac{2}{5}(n+2)=6[/tex]

A. [tex]n=-13[/tex]
B. [tex]n=-10[/tex]
C. [tex]n=17[/tex]
D. [tex]n=-17[/tex]


Sagot :

To solve the equation [tex]\(-\frac{2}{5}(n + 2) = 6\)[/tex], let's proceed step-by-step:

1. Isolate the term involving [tex]\(n\)[/tex] by eliminating the fraction:
[tex]\[ -\frac{2}{5}(n + 2) = 6 \][/tex]
Multiply both sides of the equation by [tex]\(-\frac{5}{2}\)[/tex] to cancel the fractional coefficient on the left side.
[tex]\[ \left( -\frac{2}{5} \right) \times \left( -\frac{5}{2} \right) (n + 2) = 6 \times \left( -\frac{5}{2} \right) \][/tex]
Simplifying the left side, we get:
[tex]\[ 1 \cdot (n + 2) = -15 \][/tex]
So:
[tex]\[ n + 2 = -15 \][/tex]

2. Solve for [tex]\(n\)[/tex]:
[tex]\[ n + 2 = -15 \][/tex]
Subtract 2 from both sides of the equation to isolate [tex]\(n\)[/tex]:
[tex]\[ n = -15 - 2 \][/tex]
[tex]\[ n = -17 \][/tex]

So, the solution for [tex]\(n\)[/tex] is [tex]\(-17\)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{D \; n = -17} \][/tex]