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What do the following commands return when `genre = "transcendental"`?

1. `print(genre[:-8])`
2. `print(genre[-7:9])`

A. transc, nd
B. endental, tr
C. ran, ental
D. dental, trans


Sagot :

Let's analyze the given commands step-by-step using the string "transcendental":

1. `print(genre[:-8])`

In this command, we need to understand what `genre[:-8]` does. The notation `[: -8]` means that we need to take all characters in the string `genre` from the beginning up to, but not including, the 8th character from the end of the string.

The string "transcendental" has 14 characters:
- Positions: t r a n s c e n d e n t a l
- Indices: 0 1 2 3 4 5 6 7 8 9 10 11 12 13

If we count 8 positions from the end (starting from the end), we get:
- "transcendental" -> `e` (position from the end is -8)

Therefore, the command `print(genre[:-8])` will take everything from the beginning up to, but not including, the character 'e'.

Result 1: "transc"

2. `print(genre[-7:9])`

For this command, `genre[-7:9]`, we analyze it as follows:
- `[-7:]` denotes starting the slice at the 7th character from the end.
- `[9]` denotes ending the slice at the 9th character from the start.

Counting 7 positions from the end:
- "transcendental" -> "endental" (this is starting the slice from 'e' at position -7).

Next, counting up to index 9 from the start:
- "transcendental" -> "transcend" (up to and including the 9th character)

However, since we are starting from `-7` (which is 'e') and going to `9` (which is 'd'), we effectively get the substring within this range:

So, Result 2: "nd"

The answers for each of the commands are:
1. "transc"
2. "nd"

Thus, the results from the commands are 'transc' and 'nd'. Therefore, the correct matching answer is:

transc, nd
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