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Sagot :
To find the electric potential [tex]\( V \)[/tex], you can use the relationship between electric potential energy [tex]\( U \)[/tex] and charge [tex]\( q \)[/tex]. The formula that relates electric potential [tex]\( V \)[/tex] to electric potential energy [tex]\( U \)[/tex] and charge [tex]\( q \)[/tex] is:
[tex]\[ V = \frac{U}{q} \][/tex]
Given values:
- Charge [tex]\( q = 4.5 \times 10^{-5} \)[/tex] Coulombs
- Electric potential energy [tex]\( U = 0.027 \)[/tex] Joules
Using the formula:
[tex]\[ V = \frac{0.027 \text{ J}}{4.5 \times 10^{-5} \text{ C}} \][/tex]
Perform the division:
[tex]\[ V = \frac{0.027}{4.5 \times 10^{-5}} \][/tex]
After calculating the above expression, we find:
[tex]\[ V = 600.0 \text{ V} \][/tex]
Thus, the electric potential is
[tex]\[ 600.0 \text{ V} \][/tex]
[tex]\[ V = \frac{U}{q} \][/tex]
Given values:
- Charge [tex]\( q = 4.5 \times 10^{-5} \)[/tex] Coulombs
- Electric potential energy [tex]\( U = 0.027 \)[/tex] Joules
Using the formula:
[tex]\[ V = \frac{0.027 \text{ J}}{4.5 \times 10^{-5} \text{ C}} \][/tex]
Perform the division:
[tex]\[ V = \frac{0.027}{4.5 \times 10^{-5}} \][/tex]
After calculating the above expression, we find:
[tex]\[ V = 600.0 \text{ V} \][/tex]
Thus, the electric potential is
[tex]\[ 600.0 \text{ V} \][/tex]
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