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Sagot :
To find the slope of the line passing through the points [tex]\((7,6)\)[/tex] and [tex]\((-2, -9)\)[/tex], we use the formula for the slope between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex]:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Given the points [tex]\((x_1, y_1) = (7, 6)\)[/tex] and [tex]\((x_2, y_2) = (-2, -9)\)[/tex], we can substitute these values into the slope formula:
[tex]\[ \text{slope} = \frac{-9 - 6}{-2 - 7} \][/tex]
First, simplify the numerator and the denominator:
[tex]\[ -9 - 6 = -15 \][/tex]
[tex]\[ -2 - 7 = -9 \][/tex]
Now, we have:
[tex]\[ \text{slope} = \frac{-15}{-9} \][/tex]
Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 3:
[tex]\[ \text{slope} = \frac{-15 \div 3}{-9 \div 3} = \frac{-5}{-3} = \frac{5}{3} \][/tex]
So, the slope of the line passing through the points [tex]\((7, 6)\)[/tex] and [tex]\((-2, -9)\)[/tex] is:
[tex]\[ \boxed{\frac{5}{3}} \][/tex]
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Given the points [tex]\((x_1, y_1) = (7, 6)\)[/tex] and [tex]\((x_2, y_2) = (-2, -9)\)[/tex], we can substitute these values into the slope formula:
[tex]\[ \text{slope} = \frac{-9 - 6}{-2 - 7} \][/tex]
First, simplify the numerator and the denominator:
[tex]\[ -9 - 6 = -15 \][/tex]
[tex]\[ -2 - 7 = -9 \][/tex]
Now, we have:
[tex]\[ \text{slope} = \frac{-15}{-9} \][/tex]
Simplify the fraction by dividing both the numerator and the denominator by their greatest common divisor, which is 3:
[tex]\[ \text{slope} = \frac{-15 \div 3}{-9 \div 3} = \frac{-5}{-3} = \frac{5}{3} \][/tex]
So, the slope of the line passing through the points [tex]\((7, 6)\)[/tex] and [tex]\((-2, -9)\)[/tex] is:
[tex]\[ \boxed{\frac{5}{3}} \][/tex]
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