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If [tex](3 \sqrt{7})(2 \sqrt{5})=w \sqrt{z}[/tex], what is the value of [tex]w+z[/tex]?

Answer:


Sagot :

To solve the expression [tex]\((3 \sqrt{7})(2 \sqrt{5})=w \sqrt{z}\)[/tex] and find the value of [tex]\(w + z\)[/tex], let's break the problem down step-by-step.

1. Understand the given terms:
[tex]\( \text{term1} = 3 \sqrt{7} \)[/tex]
[tex]\( \text{term2} = 2 \sqrt{5} \)[/tex]

2. Multiply the given terms:
[tex]\[ 3 \sqrt{7} \times 2 \sqrt{5} \][/tex]

3. Use the property of multiplication of radicals:
[tex]\[ (3 \cdot 2) \cdot (\sqrt{7} \cdot \sqrt{5}) \][/tex]
[tex]\[ 3 \times 2 = 6 \][/tex]
[tex]\[ \sqrt{7} \times \sqrt{5} = \sqrt{7 \times 5} = \sqrt{35} \][/tex]

4. Combine the constants with the radicals:
[tex]\[ 6 \sqrt{35} \][/tex]
So, we see [tex]\(w = 6\)[/tex] and [tex]\(z = 35\)[/tex] in the expression [tex]\(6 \sqrt{35}\)[/tex].

5. Add [tex]\(w\)[/tex] and [tex]\(z\)[/tex] together:
[tex]\[ w + z = 6 + 35 \][/tex]

6. That results in:
[tex]\[ w + z = 41 \][/tex]

So the value of [tex]\(w + z\)[/tex] is [tex]\(\boxed{41}\)[/tex].
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