IDNLearn.com provides a comprehensive solution for all your question and answer needs. Get prompt and accurate answers to your questions from our experts who are always ready to help.
Sagot :
To determine at which differences the given polynomial sequence [tex]\( a_n = 2n^4 - n^3 \)[/tex] reaches a constant value, let's follow the step-by-step process of computing the differences.
1. Identify the first few terms of the sequence:
Let's calculate [tex]\( a_n \)[/tex] for the first five integers [tex]\( n = 1, 2, 3, 4, 5 \)[/tex]:
[tex]\[ \begin{aligned} a_1 &= 2 \cdot 1^4 - 1^3 = 2 - 1 = 1, \\ a_2 &= 2 \cdot 2^4 - 2^3 = 2 \cdot 16 - 8 = 32 - 8 = 24, \\ a_3 &= 2 \cdot 3^4 - 3^3 = 2 \cdot 81 - 27 = 162 - 27 = 135, \\ a_4 &= 2 \cdot 4^4 - 4^3 = 2 \cdot 256 - 64 = 512 - 64 = 448, \\ a_5 &= 2 \cdot 5^4 - 5^3 = 2 \cdot 625 - 125 = 1250 - 125 = 1125. \end{aligned} \][/tex]
So, the sequence of terms is [tex]\( \{a_1, a_2, a_3, a_4, a_5\} = \{1, 24, 135, 448, 1125\} \)[/tex].
2. First differences:
Calculate the differences between consecutive terms:
[tex]\[ \begin{aligned} a_2 - a_1 &= 24 - 1 = 23, \\ a_3 - a_2 &= 135 - 24 = 111, \\ a_4 - a_3 &= 448 - 135 = 313, \\ a_5 - a_4 &= 1125 - 448 = 677. \end{aligned} \][/tex]
Thus, the first differences are [tex]\( \{23, 111, 313, 677\} \)[/tex].
3. Second differences:
Calculate the differences between consecutive first differences:
[tex]\[ \begin{aligned} 111 - 23 &= 88, \\ 313 - 111 &= 202, \\ 677 - 313 &= 364. \end{aligned} \][/tex]
Therefore, the second differences are [tex]\( \{88, 202, 364\} \)[/tex].
4. Third differences:
Calculate the differences between consecutive second differences:
[tex]\[ \begin{aligned} 202 - 88 &= 114, \\ 364 - 202 &= 162. \end{aligned} \][/tex]
The third differences are [tex]\( \{114, 162\} \)[/tex].
5. Fourth differences:
Calculate the differences between consecutive third differences:
[tex]\[ 162 - 114 = 48. \][/tex]
The fourth differences are [tex]\( \{48\} \)[/tex].
From the calculations above, we see that the fourth differences are constant.
Thus, the sequence [tex]\( a_n = 2n^4 - n^3 \)[/tex] reaches a constant value at the fourth differences.
Answer: 4th differences
1. Identify the first few terms of the sequence:
Let's calculate [tex]\( a_n \)[/tex] for the first five integers [tex]\( n = 1, 2, 3, 4, 5 \)[/tex]:
[tex]\[ \begin{aligned} a_1 &= 2 \cdot 1^4 - 1^3 = 2 - 1 = 1, \\ a_2 &= 2 \cdot 2^4 - 2^3 = 2 \cdot 16 - 8 = 32 - 8 = 24, \\ a_3 &= 2 \cdot 3^4 - 3^3 = 2 \cdot 81 - 27 = 162 - 27 = 135, \\ a_4 &= 2 \cdot 4^4 - 4^3 = 2 \cdot 256 - 64 = 512 - 64 = 448, \\ a_5 &= 2 \cdot 5^4 - 5^3 = 2 \cdot 625 - 125 = 1250 - 125 = 1125. \end{aligned} \][/tex]
So, the sequence of terms is [tex]\( \{a_1, a_2, a_3, a_4, a_5\} = \{1, 24, 135, 448, 1125\} \)[/tex].
2. First differences:
Calculate the differences between consecutive terms:
[tex]\[ \begin{aligned} a_2 - a_1 &= 24 - 1 = 23, \\ a_3 - a_2 &= 135 - 24 = 111, \\ a_4 - a_3 &= 448 - 135 = 313, \\ a_5 - a_4 &= 1125 - 448 = 677. \end{aligned} \][/tex]
Thus, the first differences are [tex]\( \{23, 111, 313, 677\} \)[/tex].
3. Second differences:
Calculate the differences between consecutive first differences:
[tex]\[ \begin{aligned} 111 - 23 &= 88, \\ 313 - 111 &= 202, \\ 677 - 313 &= 364. \end{aligned} \][/tex]
Therefore, the second differences are [tex]\( \{88, 202, 364\} \)[/tex].
4. Third differences:
Calculate the differences between consecutive second differences:
[tex]\[ \begin{aligned} 202 - 88 &= 114, \\ 364 - 202 &= 162. \end{aligned} \][/tex]
The third differences are [tex]\( \{114, 162\} \)[/tex].
5. Fourth differences:
Calculate the differences between consecutive third differences:
[tex]\[ 162 - 114 = 48. \][/tex]
The fourth differences are [tex]\( \{48\} \)[/tex].
From the calculations above, we see that the fourth differences are constant.
Thus, the sequence [tex]\( a_n = 2n^4 - n^3 \)[/tex] reaches a constant value at the fourth differences.
Answer: 4th differences
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.