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Sagot :
Let's solve the problem step by step:
1. Identify the original freezing point of water:
- The freezing point of pure water is [tex]\(32^{\circ}F\)[/tex].
2. Determine the effect of adding salt:
- Adding salt to water decreases its freezing point. The problem states that this decrease is [tex]\(8^{\circ}F\)[/tex].
3. Calculate the new freezing point:
- We start with the original freezing point of water, which is [tex]\(32^{\circ}F\)[/tex].
- We then subtract the decrease caused by the addition of salt.
[tex]\[ \text{New freezing point} = 32^{\circ}F - 8^{\circ}F \][/tex]
4. Perform the subtraction:
- Subtract [tex]\(8^{\circ}F\)[/tex] from [tex]\(32^{\circ}F\)[/tex].
[tex]\[ 32^{\circ}F - 8^{\circ}F = 24^{\circ}F \][/tex]
Therefore, the freezing point of water with salt added is [tex]\(24^{\circ}F\)[/tex].
1. Identify the original freezing point of water:
- The freezing point of pure water is [tex]\(32^{\circ}F\)[/tex].
2. Determine the effect of adding salt:
- Adding salt to water decreases its freezing point. The problem states that this decrease is [tex]\(8^{\circ}F\)[/tex].
3. Calculate the new freezing point:
- We start with the original freezing point of water, which is [tex]\(32^{\circ}F\)[/tex].
- We then subtract the decrease caused by the addition of salt.
[tex]\[ \text{New freezing point} = 32^{\circ}F - 8^{\circ}F \][/tex]
4. Perform the subtraction:
- Subtract [tex]\(8^{\circ}F\)[/tex] from [tex]\(32^{\circ}F\)[/tex].
[tex]\[ 32^{\circ}F - 8^{\circ}F = 24^{\circ}F \][/tex]
Therefore, the freezing point of water with salt added is [tex]\(24^{\circ}F\)[/tex].
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