IDNLearn.com offers a collaborative platform for sharing and gaining knowledge. Ask anything and receive thorough, reliable answers from our community of experienced professionals.
Sagot :
Answer:
- Methanoic acid, Ka = 1.8 × 10⁻⁴
Explanation:
At buffering capacity, the pH = pKa. This means that we can take the -log of each substance's Ka value to get the pKa and whichever of these values is closest to 4.15, will be the most appropriate acid.
Solving:
[tex]\section*{pKa:}\[\text{pKa} = -\log(K_a)\]\subsection*{Hydrofluoric Acid}\[K_a = 6.6 \times 10^{-4} \implies \text{pKa} = -\log(6.6 \times 10^{-4}) \approx \boxed{3.18}\]\subsection*{Methanoic Acid}\[K_a = 1.8 \times 10^{-4} \implies \text{pKa} = -\log(1.8 \times 10^{-4}) \approx \boxed{3.74}\]\subsection*{Ascorbic Acid}\[K_a = 4.3 \times 10^{-7} \implies \text{pKa} = -\log(4.3 \times 10^{-7}) \approx \boxed{6.37}\][/tex]
Since Methanol acid has a pKa value of 3.74, that means the pH in a buffer solution would also be 3.74 which is the closest to 4.15.
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.