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How many coefficients are in the equation [tex]6x - 9y - 10r = 3z + 4[/tex]?

A. 6
B. 5
C. 4
D. 3

Sagot :

GinnyAnsweridn
To determine how many coefficients are present in the equation [tex]\(6x - 9y - 10r = 3z + 4\)[/tex], let's break it down step-by-step.

1. Identify the Variables and Constants:
- Variables: [tex]\(x, y, r, z\)[/tex]
- Constants: Numerical values in the equation.

2. Identify the Coefficients on Each Side of the Equation:
- On the left side of the equation ([tex]\(6x - 9y - 10r\)[/tex]):
- The coefficient of [tex]\(x\)[/tex] is [tex]\(6\)[/tex].
- The coefficient of [tex]\(y\)[/tex] is [tex]\(-9\)[/tex].
- The coefficient of [tex]\(r\)[/tex] is [tex]\(-10\)[/tex].

This gives us three coefficients.

- On the right side of the equation ([tex]\(3z + 4\)[/tex]):
- The coefficient of [tex]\(z\)[/tex] is [tex]\(3\)[/tex].

This gives us one coefficient.

3. Count the Total Number of Coefficients:
- From the left side, we have three coefficients.
- From the right side, we have one coefficient.

4. Add the Coefficients Together:
- Total number of coefficients is [tex]\(3 + 1 = 4\)[/tex].

Thus, the total number of coefficients in the equation [tex]\(6x - 9y - 10r = 3z + 4\)[/tex] is [tex]\(4\)[/tex].
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