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Sagot :
Sure, let's solve for [tex]\( x \)[/tex] given the function [tex]\( g(x) = 5x + 1 \)[/tex] and [tex]\( g(x) = 41 \)[/tex].
1. Start with the given function:
[tex]\[ g(x) = 5x + 1 \][/tex]
and we know that:
[tex]\[ g(x) = 41 \][/tex]
2. Substitute 41 for [tex]\( g(x) \)[/tex] in the equation:
[tex]\[ 5x + 1 = 41 \][/tex]
3. Next, isolate the term containing [tex]\( x \)[/tex]. To do this, subtract 1 from both sides of the equation:
[tex]\[ 5x + 1 - 1 = 41 - 1 \][/tex]
This simplifies to:
[tex]\[ 5x = 40 \][/tex]
4. Now, to solve for [tex]\( x \)[/tex], divide both sides of the equation by 5:
[tex]\[ x = \frac{40}{5} \][/tex]
5. Simplify the division:
[tex]\[ x = 8 \][/tex]
Therefore, the value of [tex]\( x \)[/tex] is [tex]\( 8 \)[/tex].
1. Start with the given function:
[tex]\[ g(x) = 5x + 1 \][/tex]
and we know that:
[tex]\[ g(x) = 41 \][/tex]
2. Substitute 41 for [tex]\( g(x) \)[/tex] in the equation:
[tex]\[ 5x + 1 = 41 \][/tex]
3. Next, isolate the term containing [tex]\( x \)[/tex]. To do this, subtract 1 from both sides of the equation:
[tex]\[ 5x + 1 - 1 = 41 - 1 \][/tex]
This simplifies to:
[tex]\[ 5x = 40 \][/tex]
4. Now, to solve for [tex]\( x \)[/tex], divide both sides of the equation by 5:
[tex]\[ x = \frac{40}{5} \][/tex]
5. Simplify the division:
[tex]\[ x = 8 \][/tex]
Therefore, the value of [tex]\( x \)[/tex] is [tex]\( 8 \)[/tex].
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