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How many atoms of gold (Au, [tex]196.97 \, \text{g/mol}[/tex]) are in a gold nugget with a mass of 4.25 g?

[tex] \times 10^{[?]} \text{atoms}[/tex]


Sagot :

To determine how many atoms of gold are in a 4.25-gram gold nugget, we need to follow these steps:

1. Determine the number of moles of gold in the sample:
- The molar mass of gold is given as 196.97 g/mol.
- The mass of the gold nugget is 4.25 g.
- The formula to find the number of moles (n) is:
[tex]\[ n = \frac{\text{mass}}{\text{molar mass}} \][/tex]
- Plugging in the values:
[tex]\[ n = \frac{4.25 \, \text{g}}{196.97 \, \text{g/mol}} \approx 0.0215769 \, \text{mol} \][/tex]

2. Calculate the number of atoms in the nugget:
- Avogadro's number gives us the number of atoms per mole, which is [tex]\(6.022 \times 10^{23} \)[/tex] atoms/mol.
- To find the number of atoms, we multiply the number of moles by Avogadro's number:
[tex]\[ \text{Number of atoms} = n \times \text{Avogadro's number} \][/tex]
- Substituting the values:
[tex]\[ \text{Number of atoms} = 0.0215769 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 1.2994 \times 10^{22} \, \text{atoms} \][/tex]

In conclusion, the number of gold atoms in a 4.25-gram gold nugget is [tex]\(\approx 1.299 \times 10^{22}\)[/tex].