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Sagot :
To determine the number of moles of hydrogen in 4.70 moles of C₁₂H₂₂O₁₁ (sucrose), follow these steps:
1. Identify the number of hydrogen atoms per molecule of the compound:
In the chemical formula C₁₂H₂₂O₁₁, each molecule of sucrose contains 22 hydrogen atoms.
2. Use the given amount of moles of the compound:
You have 4.70 moles of C₁₂H₂₂O₁₁.
3. Calculate the total moles of hydrogen atoms:
Since each mole of sucrose has 22 moles of hydrogen atoms, you multiply the number of moles of the compound by the number of hydrogen atoms per molecule:
[tex]\[ \text{Total moles of hydrogen} = 4.70 \, \text{moles of C}_{12}\text{H}_{22}\text{O}_{11} \times 22 \, \text{moles of H per mole of C}_{12}\text{H}_{22}\text{O}_{11} \][/tex]
4. Perform the multiplication:
[tex]\[ 4.70 \times 22 = 103.4 \][/tex]
Therefore, there are 103.4 moles of hydrogen in 4.70 moles of C₁₂H₂₂O₁₁.
1. Identify the number of hydrogen atoms per molecule of the compound:
In the chemical formula C₁₂H₂₂O₁₁, each molecule of sucrose contains 22 hydrogen atoms.
2. Use the given amount of moles of the compound:
You have 4.70 moles of C₁₂H₂₂O₁₁.
3. Calculate the total moles of hydrogen atoms:
Since each mole of sucrose has 22 moles of hydrogen atoms, you multiply the number of moles of the compound by the number of hydrogen atoms per molecule:
[tex]\[ \text{Total moles of hydrogen} = 4.70 \, \text{moles of C}_{12}\text{H}_{22}\text{O}_{11} \times 22 \, \text{moles of H per mole of C}_{12}\text{H}_{22}\text{O}_{11} \][/tex]
4. Perform the multiplication:
[tex]\[ 4.70 \times 22 = 103.4 \][/tex]
Therefore, there are 103.4 moles of hydrogen in 4.70 moles of C₁₂H₂₂O₁₁.
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