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Sagot :
To determine the number of moles of carbon in 3.0 moles of glucose ([tex]\( \text{C}_6\text{H}_{12}\text{O}_6 \)[/tex]), follow these steps:
1. Understand the molecular formula of glucose: The molecular formula of glucose is [tex]\( \text{C}_6\text{H}_{12}\text{O}_6 \)[/tex]. This indicates that each molecule of glucose contains 6 atoms of carbon.
2. Recognize the relationship within the formula: For every 1 mole of glucose, there are 6 moles of carbon atoms, 12 moles of hydrogen atoms, and 6 moles of oxygen atoms.
3. Given the amount of glucose: We are provided with 3.0 moles of glucose.
4. Calculate the moles of carbon:
- Since each mole of glucose contains 6 moles of carbon,
- For 3.0 moles of glucose, the total number of moles of carbon can be calculated as:
[tex]\[ \text{moles of carbon} = 3.0 \, \text{moles of glucose} \times 6 \, \text{moles of carbon per mole of glucose} \][/tex]
5. Perform the multiplication:
- [tex]\[ \text{moles of carbon} = 3.0 \times 6 \][/tex]
- [tex]\[ \text{moles of carbon} = 18.0 \][/tex]
So, there are [tex]\( \boxed{18.0} \)[/tex] moles of carbon in 3.0 moles of [tex]\( \text{C}_6\text{H}_{12}\text{O}_6 \)[/tex].
1. Understand the molecular formula of glucose: The molecular formula of glucose is [tex]\( \text{C}_6\text{H}_{12}\text{O}_6 \)[/tex]. This indicates that each molecule of glucose contains 6 atoms of carbon.
2. Recognize the relationship within the formula: For every 1 mole of glucose, there are 6 moles of carbon atoms, 12 moles of hydrogen atoms, and 6 moles of oxygen atoms.
3. Given the amount of glucose: We are provided with 3.0 moles of glucose.
4. Calculate the moles of carbon:
- Since each mole of glucose contains 6 moles of carbon,
- For 3.0 moles of glucose, the total number of moles of carbon can be calculated as:
[tex]\[ \text{moles of carbon} = 3.0 \, \text{moles of glucose} \times 6 \, \text{moles of carbon per mole of glucose} \][/tex]
5. Perform the multiplication:
- [tex]\[ \text{moles of carbon} = 3.0 \times 6 \][/tex]
- [tex]\[ \text{moles of carbon} = 18.0 \][/tex]
So, there are [tex]\( \boxed{18.0} \)[/tex] moles of carbon in 3.0 moles of [tex]\( \text{C}_6\text{H}_{12}\text{O}_6 \)[/tex].
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