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To determine how many moles of hydrogen are in 3.0 moles of [tex]\( C_6H_{12}O_6 \)[/tex], follow these steps:
1. Identify the number of hydrogen atoms in one molecule of [tex]\( C_6H_{12}O_6 \)[/tex]:
- The chemical formula [tex]\( C_6H_{12}O_6 \)[/tex] reveals there are 12 hydrogen (H) atoms in one molecule of glucose.
2. Understand the relationship between moles of [tex]\( C_6H_{12}O_6 \)[/tex] and moles of hydrogen:
- Since one molecule of [tex]\( C_6H_{12}O_6 \)[/tex] contains 12 hydrogen atoms, one mole of [tex]\( C_6H_{12}O_6 \)[/tex] contains 12 moles of hydrogen atoms.
3. Calculate the total number of moles of hydrogen in the given sample:
- Given that we have 3.0 moles of [tex]\( C_6H_{12}O_6 \)[/tex], and knowing that each mole of [tex]\( C_6H_{12}O_6 \)[/tex] contains 12 moles of hydrogen atoms, we can find the total moles of hydrogen.
4. Multiply the number of moles of [tex]\( C_6H_{12}O_6 \)[/tex] by the number of hydrogen atoms per mole:
- [tex]\( 3.0 \text{ moles of } C_6H_{12}O_6 \times 12 \text{ moles of H per mole of } C_6H_{12}O_6 = 36.0 \text{ moles of hydrogen} \)[/tex].
Therefore, in 3.0 moles of [tex]\( C_6H_{12}O_6 \)[/tex], there are 36.0 moles of hydrogen. So, the answer is:
[tex]\[ 36.0 \text{ moles H} \][/tex]
1. Identify the number of hydrogen atoms in one molecule of [tex]\( C_6H_{12}O_6 \)[/tex]:
- The chemical formula [tex]\( C_6H_{12}O_6 \)[/tex] reveals there are 12 hydrogen (H) atoms in one molecule of glucose.
2. Understand the relationship between moles of [tex]\( C_6H_{12}O_6 \)[/tex] and moles of hydrogen:
- Since one molecule of [tex]\( C_6H_{12}O_6 \)[/tex] contains 12 hydrogen atoms, one mole of [tex]\( C_6H_{12}O_6 \)[/tex] contains 12 moles of hydrogen atoms.
3. Calculate the total number of moles of hydrogen in the given sample:
- Given that we have 3.0 moles of [tex]\( C_6H_{12}O_6 \)[/tex], and knowing that each mole of [tex]\( C_6H_{12}O_6 \)[/tex] contains 12 moles of hydrogen atoms, we can find the total moles of hydrogen.
4. Multiply the number of moles of [tex]\( C_6H_{12}O_6 \)[/tex] by the number of hydrogen atoms per mole:
- [tex]\( 3.0 \text{ moles of } C_6H_{12}O_6 \times 12 \text{ moles of H per mole of } C_6H_{12}O_6 = 36.0 \text{ moles of hydrogen} \)[/tex].
Therefore, in 3.0 moles of [tex]\( C_6H_{12}O_6 \)[/tex], there are 36.0 moles of hydrogen. So, the answer is:
[tex]\[ 36.0 \text{ moles H} \][/tex]
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