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To determine how many moles of hydrogen are present in 3.7 moles of the compound [tex]\(C_8H_{11}NO_2\)[/tex], we should follow these steps:
1. Identify the number of hydrogen atoms per molecule in the compound: In the formula [tex]\(C_8H_{11}NO_2\)[/tex], it's clear that there are 11 hydrogen atoms in each molecule of the compound.
2. Establish the given amount of the compound in moles: We are given 3.7 moles of [tex]\(C_8H_{11}NO_2\)[/tex].
3. Determine the number of moles of hydrogen atoms per mole of the compound: Since each mole of [tex]\(C_8H_{11}NO_2\)[/tex] contains 11 moles of hydrogen atoms, we can say:
- 1 mole of [tex]\(C_8H_{11}NO_2\)[/tex] contains 11 moles of hydrogen atoms.
4. Calculate the total moles of hydrogen in the given moles of the compound:
- If 1 mole of [tex]\(C_8H_{11}NO_2\)[/tex] contains 11 moles of hydrogen, then 3.7 moles of [tex]\(C_8H_{11}NO_2\)[/tex] will contain:
[tex]\[ 3.7 \text{ moles of } C_8H_{11}NO_2 \times 11 \text{ moles of hydrogen per mole of } C_8H_{11}NO_2 \][/tex]
5. Perform the multiplication:
[tex]\[ 3.7 \times 11 = 40.7 \][/tex]
Therefore, in 3.7 moles of [tex]\(C_8H_{11}NO_2\)[/tex], there are 40.7 moles of hydrogen atoms.
1. Identify the number of hydrogen atoms per molecule in the compound: In the formula [tex]\(C_8H_{11}NO_2\)[/tex], it's clear that there are 11 hydrogen atoms in each molecule of the compound.
2. Establish the given amount of the compound in moles: We are given 3.7 moles of [tex]\(C_8H_{11}NO_2\)[/tex].
3. Determine the number of moles of hydrogen atoms per mole of the compound: Since each mole of [tex]\(C_8H_{11}NO_2\)[/tex] contains 11 moles of hydrogen atoms, we can say:
- 1 mole of [tex]\(C_8H_{11}NO_2\)[/tex] contains 11 moles of hydrogen atoms.
4. Calculate the total moles of hydrogen in the given moles of the compound:
- If 1 mole of [tex]\(C_8H_{11}NO_2\)[/tex] contains 11 moles of hydrogen, then 3.7 moles of [tex]\(C_8H_{11}NO_2\)[/tex] will contain:
[tex]\[ 3.7 \text{ moles of } C_8H_{11}NO_2 \times 11 \text{ moles of hydrogen per mole of } C_8H_{11}NO_2 \][/tex]
5. Perform the multiplication:
[tex]\[ 3.7 \times 11 = 40.7 \][/tex]
Therefore, in 3.7 moles of [tex]\(C_8H_{11}NO_2\)[/tex], there are 40.7 moles of hydrogen atoms.
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