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Find the 20th term of the arithmetic sequence:

[tex]\[ 100, 96, 92, 88, \ldots \][/tex]

20th term =


Sagot :

To find the 20th term of the arithmetic sequence [tex]\(100, 96, 92, 88, \ldots\)[/tex], we can follow these steps:

1. Identify the first term ([tex]\(a_1\)[/tex]): The first term of the sequence is [tex]\(100\)[/tex].

2. Determine the common difference ([tex]\(d\)[/tex]): The common difference can be found by subtracting any term from the preceding term. For example:
[tex]\[ d = 96 - 100 = -4 \][/tex]

3. Use the formula for the [tex]\(n\)[/tex]th term of an arithmetic sequence: The formula to find the [tex]\(n\)[/tex]th term ([tex]\(a_n\)[/tex]) is:
[tex]\[ a_n = a_1 + (n - 1)d \][/tex]
In this case, we want to find the 20th term ([tex]\(a_{20}\)[/tex]).

4. Substitute the known values into the formula:
[tex]\[ a_{20} = 100 + (20 - 1)(-4) \][/tex]

5. Calculate the expression inside the parentheses:
[tex]\[ 20 - 1 = 19 \][/tex]

6. Multiply the common difference by the result:
[tex]\[ 19 \times (-4) = -76 \][/tex]

7. Add this product to the first term:
[tex]\[ a_{20} = 100 + (-76) = 100 - 76 = 24 \][/tex]

Therefore, the 20th term of the arithmetic sequence is [tex]\( \boxed{24} \)[/tex].