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A circle centered at the origin has a radius of 12.

What is the equation of the circle?

A. [tex]x^2 + y^2 = 12[/tex]
B. [tex]x^2 + y^2 = 24[/tex]
C. [tex]x^2 + y^2 = 36[/tex]
D. [tex]x^2 + y^2 = 144[/tex]


Sagot :

To determine the equation of a circle centered at the origin with a given radius, we can use the standard form of the equation for a circle. The general form for the equation of a circle centered at the origin [tex]\((0,0)\)[/tex] with a radius [tex]\(r\)[/tex] is:

[tex]\[ x^2 + y^2 = r^2 \][/tex]

We are given that the radius [tex]\(r\)[/tex] of the circle is 12. Plugging this value into the equation, we get:

[tex]\[ r = 12 \][/tex]

Substitute [tex]\(r\)[/tex] with 12 in the standard form equation:

[tex]\[ x^2 + y^2 = 12^2 \][/tex]

Now, compute [tex]\(12^2\)[/tex]:

[tex]\[ 12^2 = 144 \][/tex]

Therefore, the equation of the circle centered at the origin with a radius of 12 is:

[tex]\[ x^2 + y^2 = 144 \][/tex]

Thus, the correct answer is:

D. [tex]\(x^2 + y^2 = 144\)[/tex]
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