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What is the momentum of a 15 kg tire rolling down a hill at [tex]3 \, \text{m/s}[/tex]?

A. [tex]5 \, \text{kg} \cdot \text{m/s}[/tex]
B. [tex]18 \, \text{kg} \cdot \text{m/s}[/tex]
C. [tex]45 \, \text{kg} \cdot \text{m/s}[/tex]
D. [tex]60 \, \text{kg} \cdot \text{m/s}[/tex]


Sagot :

To determine the momentum of an object, we use the formula for momentum:

[tex]\[ \text{momentum} = \text{mass} \times \text{velocity} \][/tex]

In this problem, we are given:
- The mass of the tire ([tex]\(m\)[/tex]) is [tex]\(15 \, \text{kg}\)[/tex].
- The velocity of the tire ([tex]\(v\)[/tex]) is [tex]\(3 \, \text{m/s}\)[/tex].

Using the formula for momentum, we can substitute the given values:

[tex]\[ \text{momentum} = 15 \, \text{kg} \times 3 \, \text{m/s} \][/tex]

Multiplying these values together:

[tex]\[ \text{momentum} = 45 \, \text{kg} \cdot \text{m/s} \][/tex]

Therefore, the momentum of the 15 kg tire rolling down the hill at [tex]\(3 \, \text{m/s}\)[/tex] is:

[tex]\[ \boxed{45 \, \text{kg} \cdot \text{m/s}} \][/tex]
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