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Sagot :
To find [tex]\( f(-2) \)[/tex] for the function [tex]\( f(x) = x^2 + 2x - 10 \)[/tex], follow these steps:
1. Substitute [tex]\(-2\)[/tex] into the function:
[tex]\[ f(-2) = (-2)^2 + 2(-2) - 10 \][/tex]
2. Calculate the square of [tex]\(-2\)[/tex]:
[tex]\[ (-2)^2 = 4 \][/tex]
3. Multiply [tex]\(2\)[/tex] by [tex]\(-2\)[/tex]:
[tex]\[ 2 \cdot (-2) = -4 \][/tex]
4. Substitute these values back into the expression:
[tex]\[ f(-2) = 4 + (-4) - 10 \][/tex]
5. Perform the addition and subtraction:
[tex]\[ f(-2) = 4 - 4 - 10 = -10 \][/tex]
Therefore, [tex]\( f(-2) = -10 \)[/tex].
Thus, the correct answer is [tex]\(-10\)[/tex].
1. Substitute [tex]\(-2\)[/tex] into the function:
[tex]\[ f(-2) = (-2)^2 + 2(-2) - 10 \][/tex]
2. Calculate the square of [tex]\(-2\)[/tex]:
[tex]\[ (-2)^2 = 4 \][/tex]
3. Multiply [tex]\(2\)[/tex] by [tex]\(-2\)[/tex]:
[tex]\[ 2 \cdot (-2) = -4 \][/tex]
4. Substitute these values back into the expression:
[tex]\[ f(-2) = 4 + (-4) - 10 \][/tex]
5. Perform the addition and subtraction:
[tex]\[ f(-2) = 4 - 4 - 10 = -10 \][/tex]
Therefore, [tex]\( f(-2) = -10 \)[/tex].
Thus, the correct answer is [tex]\(-10\)[/tex].
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