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Sagot :
To find the tangential speed of the satellite, the first step Enrique should take is to use the correct units for time. Given that [tex]\( T = 18 \)[/tex] days, Enrique should convert the orbital period into seconds.
To convert the orbital period from days to seconds, Enrique would use the following conversion factors:
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
Hence,
[tex]\[ T \ (\text{seconds}) = T \ (\text{days}) \times 24 \ (\text{hours/day}) \times 60 \ (\text{minutes/hour}) \times 60 \ (\text{seconds/minute}) \][/tex]
Plugging in the values:
[tex]\[ T \ (\text{seconds}) = 18 \ (\text{days}) \times 24 \ (\text{hours/day}) \times 60 \ (\text{minutes/hour}) \times 60 \ (\text{seconds/minute}) \][/tex]
Calculating these,
[tex]\[ T \ (\text{seconds}) = 18 \times 24 \times 60 \times 60 \][/tex]
Therefore,
[tex]\[ T = 1555200 \ \text{seconds} \][/tex]
So, the first thing Enrique should do is convert the orbital period to seconds.
To convert the orbital period from days to seconds, Enrique would use the following conversion factors:
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
Hence,
[tex]\[ T \ (\text{seconds}) = T \ (\text{days}) \times 24 \ (\text{hours/day}) \times 60 \ (\text{minutes/hour}) \times 60 \ (\text{seconds/minute}) \][/tex]
Plugging in the values:
[tex]\[ T \ (\text{seconds}) = 18 \ (\text{days}) \times 24 \ (\text{hours/day}) \times 60 \ (\text{minutes/hour}) \times 60 \ (\text{seconds/minute}) \][/tex]
Calculating these,
[tex]\[ T \ (\text{seconds}) = 18 \times 24 \times 60 \times 60 \][/tex]
Therefore,
[tex]\[ T = 1555200 \ \text{seconds} \][/tex]
So, the first thing Enrique should do is convert the orbital period to seconds.
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