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Enrique is given information about a satellite orbiting Earth.

[tex]\[
\begin{array}{l}
r=3.8 \times 10^8 \text{ m} \\
T=18 \text{ days}
\end{array}
\][/tex]

In order to calculate the tangential speed of the satellite, what should Enrique do first?

A. Convert the radius to kilometers
B. Convert the orbital period to seconds
C. Find the square root of the radius
D. Find the square root of the orbital period


Sagot :

To find the tangential speed of the satellite, the first step Enrique should take is to use the correct units for time. Given that [tex]\( T = 18 \)[/tex] days, Enrique should convert the orbital period into seconds.

To convert the orbital period from days to seconds, Enrique would use the following conversion factors:
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds

Hence,
[tex]\[ T \ (\text{seconds}) = T \ (\text{days}) \times 24 \ (\text{hours/day}) \times 60 \ (\text{minutes/hour}) \times 60 \ (\text{seconds/minute}) \][/tex]

Plugging in the values:
[tex]\[ T \ (\text{seconds}) = 18 \ (\text{days}) \times 24 \ (\text{hours/day}) \times 60 \ (\text{minutes/hour}) \times 60 \ (\text{seconds/minute}) \][/tex]

Calculating these,
[tex]\[ T \ (\text{seconds}) = 18 \times 24 \times 60 \times 60 \][/tex]

Therefore,
[tex]\[ T = 1555200 \ \text{seconds} \][/tex]

So, the first thing Enrique should do is convert the orbital period to seconds.