Discover new perspectives and gain insights with IDNLearn.com's diverse answers. Ask your questions and receive reliable, detailed answers from our dedicated community of experts.
Sagot :
Hi Kally
Here is what I was able to come up!
4/x-2/x^2y^3
Double check it ok...
Here is what I was able to come up!
4/x-2/x^2y^3
Double check it ok...
[tex]\frac{4y}{xy}-\frac{2x}{xy^3}=\frac{4}{x}-\frac{2}{y^3}\\\\\\\frac{4y}{xy}-\frac{2x}{xy^3}=\frac{4y^3}{xy^3}-\frac{2x}{xy^3}=\frac{4y^3-2x}{xy^3}[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.