BlueBerryPieidn
Answered

IDNLearn.com makes it easy to find accurate answers to your specific questions. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.

Find the values of k that make [tex]2x^{2}+kx+7[/tex] factorable.

Sagot :

the values of k that make >      2x² + kx + 7     factorable
the values of k are      9 & 15
thus
(2x² + 9x + 7)  =      (2x + 7)(x+ 1)              k -9
(2x²  + 15x + 7)  =    (2x +1)(x+7)                K  =15
Kate200468idn
[tex]1)\\(2x+1)(x+7)=2x^2+14x+x+7=2x^2+15x+7\ \ \Rightarrow\ \ k=15\\\\2)\\(2x-1)(x-7)=2x^2-14x-x+7=2x^2-15x+7\ \ \Rightarrow\ \ k=-15\\\\3)\\(2x+7)(x+1)=2x^2+2x+7x+7=2x^2+9x+7\ \ \Rightarrow\ \ k=9\\\\4)\\(2x-7)(x-1)=2x^2-2x-7x+7=2x^2-9x+7\ \ \Rightarrow\ \ k=-9\\\\\\Ans.\ there\ are\ four\ solutions:\ k\in \{15;-15;9;-9\}[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.