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y=-3x+5

5x - 4y= -3

solvining systems of equations by substitution

Sagot :

[tex]\left\{\begin{array}{ccc}y=-3x+5\\5x-4y=-3\end{array}\right\\\\\\substitute\\\\5x-4(-3x+5)=-3\\5x+12x-20=-3\\17x-20=-3\\17x=-3+20\\17x=17\ \ \ \ /:17\\x=1\\\\y=-3\cdot1+5=-3+5=2\\\\ \left\{\begin{array}{ccc}x=1\\y=2\end{array}\right[/tex]
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